The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
This volume is 6,197 399 5 at 25 0C.
This volume is 0,449 L at 0 0C.
The volume occupied by gas molecules is negligible when compared to volume occupied by the gas.The collisions between gas molecules-gas molecules and gas molecules-walls of the container are perfectly elastic.
No, the volume occupied by one mole of a gas at a given temperature and pressure is the same for all gases, according to Avogadro's hypothesis and the ideal gas law. This is known as the molar volume of a gas, which is approximately 22.4 liters at standard temperature and pressure (STP).
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
This volume is 6,197 399 5 at 25 0C.
This volume is 0,449 L at 0 0C.
The volume occupied by 0.25 mol of any ideal gas at standard temperature and pressure (STP) is approximately 5.6 L. This is based on the molar volume of an ideal gas at STP, which is around 22.4 L/mol.
The volume that 2.4 moles of chlorine gas would occupy depends on the temperature and pressure of the gas, according to the ideal gas law (PV = nRT). At standard temperature and pressure (STP), which is 0°C and 1 atm pressure, 2.4 moles of chlorine gas would occupy approximately 53.75 liters.
The volume occupied by gas molecules is negligible when compared to volume occupied by the gas.The collisions between gas molecules-gas molecules and gas molecules-walls of the container are perfectly elastic.
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
No, the volume occupied by one mole of a gas at a given temperature and pressure is the same for all gases, according to Avogadro's hypothesis and the ideal gas law. This is known as the molar volume of a gas, which is approximately 22.4 liters at standard temperature and pressure (STP).
The ideal gas law does not account for the volume occupied by gas particles and the interactions between gas molecules.
I would assume chlorine gas and standard temperature an atmospheric pressure. Using the ideal gas equation. PV = nRT (1 atm)(X volume) = (2.4 moles Cl2)(0.08206 Mol*K/L*atm)(298.15 K) Volume = 59 Liters of chlorine gas --------------------------------------------
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
Volume is the amount of 3-dimensional space occupied by an object. It could be a liquid, but it can also be a gas. For example, a glass of air.
To calculate the volume of chlorine gas produced, you need to know the molar mass of chlorine and use the ideal gas law equation. First, convert the mass of chlorine gas to moles using its molar mass. Then use the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. Finally, you can solve for V to find the volume in liters.