At 22.4 liters a mole at STP, and the molar mass of Cl2 being 71, 17.32 g is about .242 moles. Multiply the moles by standard volume and you get 5.43 liters.
To calculate the amount of chlorine in 50 cubic meters of water at 50 parts per million, first convert cubic meters to liters (1 cubic meter = 1000 liters). Then, use the concentration of 50 parts per million (ppm) to find the amount of chlorine. This would result in 50 liters of chlorine in 50 cubic meters of water at 50 ppm.
88
At standard temperature and pressure (STP), one mole of gas occupies 22.4 liters. To find the number of moles in 15.7 liters of chlorine gas, divide 15.7 liters by 22.4 liters/mole, which gives approximately 0.699 moles. Since one mole contains Avogadro's number of molecules (approximately (6.022 \times 10^{23}) molecules/mole), the total number of molecules is about (0.699 \times 6.022 \times 10^{23} \approx 4.21 \times 10^{23}) molecules.
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
266,86 g aluminium chloride are obtained.
Since the reaction ratio is 1:1 for hydrogen and chlorine, the amount of HCl produced will be the same as the amount of hydrogen used, which is 5.7 L. So, 5.7 liters of HCl are produced in the reaction.
7 liters approximately
The volume is 254,82 L.
To calculate the amount of chlorine in 50 cubic meters of water at 50 parts per million, first convert cubic meters to liters (1 cubic meter = 1000 liters). Then, use the concentration of 50 parts per million (ppm) to find the amount of chlorine. This would result in 50 liters of chlorine in 50 cubic meters of water at 50 ppm.
2.0 billion gallons
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
75 g sodium chloride contain 29,75 g sodium.
When salt (NaCl) is split by electrolysis, one mole of sodium (Na) and one mole of chlorine (Cl2) gas are produced. The molar mass of NaCl is 58.44 g/mol, so 40.0 g of NaCl is approximately 0.68 moles. Therefore, 0.68 moles of chlorine gas are produced.
You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor). However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine. Cl2 + 2KI --> 2 KCl + I2
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
If everything is under gaseous condition and with equal pressure and temperature, then also 4.0 L SO3 gas is produced from 4.0 L SO2,g.
88