A #2 copper wire with an insulation factor of 60, 75 and 90 degrees C is rated at 100, 115 and 120 amps respectively.
There are several amperage ratings on AC compressors/motors. Locked Motor Amperage (LRA) is the amperage that the motor is fused for. The load of the motor is expressed in amperage or wattage, which is probably the case here. Low amperage readings on an AC unit being charged by amperage load would indicate low freon. High amperage readings indicate overcharge when charging by the amperage load. AC units are not accurately charged by amperage readings and the efficiency of motors is not expressed in amperage readings.
Each appliance has its own amperage. This can be shown by looking at the label of each appliance. A circuit is protected by a breaker which has a trip limit. By continually adding more amperage from different appliances, the circuit becomes overloaded. When the circuits limit is reached because of the additive effect of more appliances to the circuit the breaker will trip. This disconnects the appliance loads from the distribution panel supply and prevents over loading of the conductors of that circuit. Without removing some of the load amperage, the breaker will keep tripping when reset.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
The relation between amperage and capacitance is that amperage is equals to capacitance times the rate of voltage change over time. This voltage refers to instantaneous voltage.
20 Amp
Typically 30 amps.
Amperage is electric current of flow.
The amperage of a T2L 250v fuse is typically 8 amps. It is a misconception that it has an amperage of 3.
A #2 copper wire with an insulation factor of 60, 75 and 90 degrees C is rated at 100, 115 and 120 amps respectively.
There are several amperage ratings on AC compressors/motors. Locked Motor Amperage (LRA) is the amperage that the motor is fused for. The load of the motor is expressed in amperage or wattage, which is probably the case here. Low amperage readings on an AC unit being charged by amperage load would indicate low freon. High amperage readings indicate overcharge when charging by the amperage load. AC units are not accurately charged by amperage readings and the efficiency of motors is not expressed in amperage readings.
Circuits are limited for a few reasons firstly because certain size wiring can only handle so much voltage and amperage before it could fail secondly wiring heats up when more amperage is drawn through it which can create fires or burning out of the circuit most appliances draw set amount of current and amperage if you have a low amperage appliance Eg pool pump drawing 4 amps and the windings start to fail the motor can start drawing excessive amperage creating a hazard, if you had a large circuit it may never trip the breaker indicating a fault with the appliance which can cause catastrophic failure.
It is ok to use a fuse with a higher amperage rating and not ok to use a fuse with a smaller amperage rating why?
Each appliance has its own amperage. This can be shown by looking at the label of each appliance. A circuit is protected by a breaker which has a trip limit. By continually adding more amperage from different appliances, the circuit becomes overloaded. When the circuits limit is reached because of the additive effect of more appliances to the circuit the breaker will trip. This disconnects the appliance loads from the distribution panel supply and prevents over loading of the conductors of that circuit. Without removing some of the load amperage, the breaker will keep tripping when reset.
This doesn't make sense, "current" is "amperage" so the higher the voltage the lower the amperage, and the lower the voltage the higher the amperage.
Scientists can use laboratory beakers in various ways depending upon their experiment. Beakers can be used to measure liquids, hold items or even as the area to conduct an experiment in.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R