C3H8 + 5O2 --> 3CO2 + 4H2O
The balanced equation for the burning of propane (C3H8) is: C3H8 + 5O2 -> 3CO2 + 4H2O
The balanced equation for the monobromination of propane is C3H8 + Br2 -> C3H7Br + HBr.
Not sure
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
If you're talking about a chemical equation for a situation where you have an environment containing only methane and propane, there can be no balanced equation because with no oxygen, neither gas will burn.
The combustion of propane (C3H8) can be represented by the balanced chemical equation: (C3H8 + 5O2 \rightarrow 3CO2 + 4H2O). According to this equation, 1 mole of propane requires 5 moles of oxygen for complete combustion. Therefore, 5 moles of oxygen are needed for the reaction when burning 1 mole of propane.
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
The chemical equation for burning propane in a grill is: C3H8 + 5 O2 → 3 CO2 + 4 H2O. This equation represents the combustion of propane, where propane (C3H8) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O) as products.
The balanced chemical equation for burning C18H38 in air is: 2C18H38 + 55O2 → 36CO2 + 38H2O
The balanced chemical equation for magnesium burning in oxygen is: 2Mg + O2 -> 2MgO
No, the equation you provided is not balanced. The correct balanced equation for the combustion of propane is C3H8 + 5 O2 → 3 CO2 + 4 H2O. The equation you provided appears to have a typographical error.
Chemical formula of propane is C3H8.When propane combines with oxygen in the presence of heat source, we get an exothermic reaction.C3H8 + O2 --> Exothermic reaction (burns with bluish flame along with carbon dioxide, water and particulate matter).