A Bus is a set of data/control lines which are basically just a group of wires. e.g if 8085 wants to send 0xFF (255) to an Output device, it would make all the lines of the data bus high, bcoz 0xFF is 11111111 in binary, that is to say all the wires of the bus are 1. (1 means at +5V). -munish
It provides timing signals.
The 8086/8088 microprocessor family is a 16 bit microprocessor. The 8086 implementation also has a 16 bit data bus, but the 8088 implementation has an 8 bit data bus, comparable to the 8085. The 8088 implementation was intended as a logical upgrade from the 8085, while keeping the complexity of the system on an equal footing as the 8085.
Even though the 8085 is an 8 bit microprocessor, it can address 64K memory, because it has a 16 bit address bus.
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
The 8085 has a 16 bit address bus. As such, it can access 216, or 65,536 bytes. System design, of course, will place limits on that, as you need to share this space with code, data, and stack.
The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.
The Intel 8085 is an 8 bit microprocessor created in 1977.The Intel 8086 is a 16 bit microprocessor created in 1978. The 8086 was the first chip to start the x86 architecture family.8085 contains 16-bit address bus and 8-bit data bus8086 contains 20-bit address bus and 16-bit data bus..In 8085 the clock speed is 3MHZwhere as in 8086 the clock speed is 5MHZ.there are two differences btw 8085&80861. 8086 has 6 byte queue but 8085 has 4 byte queue2. 8086 has 16 bit data bus where as 8085 has 8 bit data bus
The 8085 microprocessor's AD bus goes into high impedance state before switching as a data input bus because you don't want two bus drivers driving the bus at the same time. You give the bus time to float between transfer of control, otherwise there will be large power transients at switchover, and you could damage the drivers.
The HOLD pin on the 8085 is an external request for control of the bus. Upon receipt of HOLD, the 8085 will complete its current cycle and assert HLDA (HOLD Acknowledge), and then it will float the address, data, and control bus one half clock cycle later. The external hardware is then free to use the bus. When it is done, it releases HOLD, the 8085 releases HLDA, and the 8085 takes control of the bus and continues with the next cycle. HOLD is used by external DMA controllers, such as the 8257, to transfer data to and from memory on behalf of high speed peripherals, without requiring 8085 attention to that data transfer.
The CLK signal in the 8085 is the system clock, which is the External Input Frequency or Crystal divided by two. It can be used to develop bus control logic, because it is essentially the inverse of ALE for one half clock cycle.
The 8085 was the next generation of the 8080, providing operation on a single +5V power supply, a multiplexed address/data bus, integration of the system controller and clock generator, new automatically vectored interrupts, a few 16 bit instructions, and serial I/O.
The 8085 microprocessor is an 8-bit microprocessor introduced by Intel in 1976. It is a popular microprocessor used in many early computer systems and embedded devices. The 8085 has a 16-bit address bus and an 8-bit data bus, with a clock speed ranging from 2 to 3 MHz. It has a total of 74 instructions in its instruction set architecture.