The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.
64 kb
The 8085 microprocessor is an 8-bit processor with a 16-bit address bus. This means it can access a maximum of 64 KB (2^16) of memory. The 8085 can address memory locations from 0000H to FFFFH, totaling 64 KB of memory space. This limitation is due to the 16-bit address bus, which can only address up to 64 KB of memory.
The Commodore 64 was equipped with 64 kilobytes (KB) or 65536 bytes of memory (64*1024). It was possible to expand this memory with a memory expansion plugged in the back although the 6510 CPU could only address 64 kb so these had methods for copying data up and down from the memory expansion to the system memory.
It works on 8 bit lower address lines has to be multiplexed with data lines Appropriate control signals have to be generated to interface with memory and I/O devices 8 bit processors are slow Memory is just 64 kb By Anmol Bhardwaj SUSCET Tangori Mohali ( India)
The Intel 8085 microprocessor uses an 8-bit data bus and a 16-bit address bus. It can address 64 KB of memory, with each memory location capable of storing a byte. Therefore, the maximum positive number that can be represented in an 8-bit register is 255 (2^8 - 1), while in a 16-bit address space, the maximum is 65,535 (2^16 - 1) when considering the entire memory range.
The 8051 microcontroller has a maximum data memory capacity of 64 KB, which includes both internal and external RAM. Internally, it has 128 bytes of RAM and can be expanded to utilize external memory through its address bus. The architecture allows for addressing external RAM, but the practical limit often depends on the specific implementation and additional circuit design.
It has 64 KB of L1 cache per core and 4 MB of L2 cache.
The stack size of Intel's 8085 microprocessor is theoretically 64 kb, but the real limit is a function of memory and program architecture and layout. The stack pointer is 16 bits, but that is not the same as stack size.
KB = Kilo bytes which is equal to 1,000 bytes :)
The 8086 was only capable of addressing 1Mbyte of memory. It was divided into segments of 65536 bytes (64 KB) each meaning about 16 segments.
Expanded memory was to use part of the remaining 384 KB, normally dedicated to communication with peripherals, for program memory as well. In order to fit potentially much more memory than the 384 KB of free address space would allow, a bankingscheme was devised, where only selected portions of the additional memory would be accessible at the same time. Originally, a single 64 KB window of memory was possible; later this was made more flexible. Applications had to be written in a specific way in order to access expanded memory.
KB and MB stand for kilobyte (1,024 bytes) and megabyte (1,024 kilobytes). They are units of measurement of the storage capacity of computer memory, hard drives, USB sticks, DVD ROMs, etc.