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Maximum RAM capacity of 8086 processor?
The 8086/8088 can address a maximum of 220, or 1,048,576, or 1 MB of memory.
What is the maximum memory address space that the processor can access directly if it is connected to a 16 bit memory considering a hypothetical microprocessor generating a 16-bit address?
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
Why memory capacity of 8085 mp is 64 KB?
The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.
What are the maximum positive numbers can be stored in Intel 8085?
The Intel 8085 microprocessor uses an 8-bit data bus and a 16-bit address bus. It can address 64 KB of memory, with each memory location capable of storing a byte. Therefore, the maximum positive number that can be represented in an 8-bit register is 255 (2^8 - 1), while in a 16-bit address space, the maximum is 65,535 (2^16 - 1) when considering the entire memory range.
What type of memory uses a 16-bit path?
16-bit memory
What is the maximum directly addressable memory capacity of 64 bit microprocessor having 64-bit instruction composedof two fields the first 2 bytes for op code and the remaining for the operand addres?
A 64-bit microprocessor can theoretically address 2^64 bytes of memory, which equals 16 exabytes. However, in this case, the instruction format specifies that the first 2 bytes are for the opcode, leaving 62 bits for the operand address. Therefore, the maximum directly addressable memory capacity is 2^62 bytes, which equals 4 petabytes.
Maximum memory address space that the processor can access directly if it is connected to a 16-bit memory?
Max. memory address space= 216 X 2 bytes = 128 Kbytes
Why address capability of 8085 is 64 bit?
The 8085 microprocessor has a 16-bit address bus, allowing it to address a maximum of (2^{16}) memory locations, which equals 65,536 bytes or 64 KB of memory. This limitation is due to the architecture of the 8085, where each address corresponds to a unique byte in memory. Therefore, while the term "64-bit" may be misleading in this context, it actually refers to the maximum addressable memory space rather than a true 64-bit capability.
What is the maximum and minimum signed number that can be stored in a memory location in the 8086 processor?
The 8086/8088 processor is a 16 bit processor. In a 16 bit two's complement notation, the maximum number is 0x7FFF, or 32767, while the minimum number is 0x8000, or -32768.
What is the external data memory capacity of 8051 and why?
65536 bytes, because the 8051 family has a 16 bit external address buss.
What is minimum and maximum segment size in 8086?
In 8086 microprocessor the total memory addressing capability is 1 mega bytes. For representing 1 mb there are minimum 4 hex digits are required i.e, 20 bits. but 8086 has fourteen 16-bit registers. That is there are no registers for representing 20 bit address. So,the total memory is divided into 16 logical segments and each segment capacity is 64 kb(kilo bytes). That is 16*64kb=1 mb.So,for representing 64 kb only 16 bit register is sufficient.
How much maximum memory size that 8085 can access?
The 8085 microprocessor is an 8-bit processor with a 16-bit address bus. This means it can access a maximum of 64 KB (2^16) of memory. The 8085 can address memory locations from 0000H to FFFFH, totaling 64 KB of memory space. This limitation is due to the 16-bit address bus, which can only address up to 64 KB of memory.
