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If you assume that it has a 16-bit data bus, then it would be 128k
so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address)
16bits = 2 bytes (memory)
so through a 16 bit memory, it can access 2*64k, which is 128k
alternatively, if its 8bit memory, 8bits=1byte
1*64k = 64k
I'm no expert, and i was searching for the answer myself, hope this helped
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