0
What is concentration of HCl given 17.65 mL of 0.110M sodium hydroxide solution needed to titrate 25.00 mL of HCl solution?
Wiki User
∙ 13y ago
Use v1*C1=v2*C2,
so:
25.00 mL * [HCl] = (17.65 mL * 0.110 M)
thus:
[HCl] = (17.65 mL * 0.110 M) / 25.00 mL = 0.07766 M = 0.0777 mol HCl / L (rounded to 3 significants)
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
What are the components of titration?
A titrant, a titrate and an indicator (if needed).
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
97.8 - 98.2 98 worked for me
How do you calculate the concentration of EDTA in titration?
in order to titrate a sample of solution, lets take an example. If we have a solution of 1.569 mg of Coso4, which has a (155.0g/mol ratio) per mill. A question may ask us to find the volume of Edta needed of titrate an aliqout of this solution. So lets take a random number of 0.007840 M EDTA and be asked to titrate A 25.00ML Aliqout of this solution. How do we find the volume of EDTA needed.....? well first we use the numbers given, 1.569 mg CoSo4/ ml x (1g/1000mg)(1molcoso4/155.0g)(1molEDTA/1mol CoSo4) calculating this out should give 1.012 x 10 ^-5 mol of EDTA per ml. we then multuply the moles of EDTA which react with 1.569 ml of COso4 by 25.00 ml 1.012x10^-5 mol edta (25.00ml)= 2.531 x 10^-4 mol of edta. This is the amount of moles in the new solution. Now we need to find the amount of moles per liter of the specific concentration of EDTA. so we multiply 2.531x10^-4 mol edta x (1L/0.007840 mol) to give 0.03228 Liters of 32.28 ml .
You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml?
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
What is the molarity of an HCl solution if 43.6 mL of a 0.125 M KOH solution are needed to titrate a 25.0 mL sample of the acid according to the equation below?
What is the molarity of an HCl solution if 43.6 mL of a 0.125 M KOH solution are needed to titrate a 25.0 mL sample of the acid according to the equation below?
How many grams of sodium hydroxide are needed to make 250. ml of a 7.80 M solution?
The molecular mass of sodium hydroxide is 39,9971 g.A 7,8 M solution has a concentration of 311,977 g/L.For 250 mL you need 311,977/4 g so 78 g NaOH.
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 3.50L of 0.700 M nitric acid solution?
98g
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200M nitric acid solution?
262 - 266
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200 M nitric acid solution?
262 - 266
What are the components of titration?
A titrant, a titrate and an indicator (if needed).
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
97.8 - 98.2 98 worked for me
What is the amount of solute needed to form a saturated solution?
it is solubility
What ratio of hydrated lime copper sulphate is needed to make 15 liters of solution?
Depending on the desired concentration of the solution !
How many liters of 5.00 M hydrochloric acid solution are needed to completely neutralize the magnesium hydroxide?
0.0532
How many grams of solute are required to make a 918 mL solution of sodium hydroxide with a concentration of 0.4922 M?
Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================
What volume in ml of a 0.03455 M calcium hydroxide solution would be needed to completely react with 32.76 ml of a 0.0215 M phosphoric acid solution?
Volume mL= 32.76 mL x 0.0215 M/ 0.03455 = 20.386 mL calcium hydroxide solution.
