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Answered 2012-02-29 07:38:54

Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples:

class Car {

Car() { }

Car(String s) { }

}

The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments

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really there is no difference between constructor overloading and metho overloading


how many constructer can be defined in class in overloading of java programming


this in java is a keyword that refers to the current object of the class. It is also used in constructor overloading when you want to invoke one constructor from another within the same class.


I think constructor overloading is the concept of polymorphism.


When we are initializing our object with different internal state then we can use the constructor overloading.


yes,because in constructor overloading constructor have same and different parameter list. In method overloading method have same name and different parameter list.



The first thing to note about constructor overloading is that Java creates a no argument constructor for you if and only if you have not typed a constructor yourself. Every class has a constructor even abstract ones (default no argument constructor). Abstract constructors are always executed. To overload a constructor you can do the following: class Test { String name; Test(String n) { name = n; System.out.println("Constructing Test Object named: " + name); } } In the case above we are overloading the default no argument constructor with a constructor that takes a String parameter. You can write you own no argument constructor as follows: class Test { Test() { System.out.println("Constructing Test Object"); } } To override our own no argument constructor we do this: class Test { Test() { // our no argument constructor System.out.println("Constructing Test Object"); } String name; Test(String n) { // overloading our no argument constructor with this // constructor that take a String parameter name = n; System.out.println("Constructing Test Object named: " + name); } }


Operator overloading is not possible in Java.


No. Java does not support copy constructor


Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class.


Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class. For example, if a client knows the Car name, they can pass that to a Car constructor that takes a string. But if they don't know the name, the client can call the no-arg constructor and that constructor can supply a default name.


no you can have a class with no public methods and even with a a private constructor public class Example { //constructor private Example(){ } }


These are two different things. "Super" is used in inheritance - if class B inherits from class A, and we want the constructor of B to do the same things the constructor of A does (and maybe more things), we can call A's constructor in B's constructor: public B() { super(); ...... } Notice that it must be the first line in B's constructor. "This" is used in case of overloading, to call a function aith the same name. For example, if we have a constructor that receives one argument, and we it want to have a default value of 0, we can write: public C() { this(0); }


Constructor overloading, just like any function's overloading, is where more than one configuration of parameters exists for the function. Based on the number and type of the parameters, different versions of the function can be resolved by the linker. This is typically used in the constructor as the default constructor (no parameters), the copy constructor (one reference parameter of the same type as the class), and the conversion constructor (any other combination of parameters).


Operator overloading refers to redefining what the mathematical operators (+-*/) do when applied to different objects. Java does not support operator overloading.


A parameterized constructor in java is just a constructor which take some kind of parameter (variable) when is invoked. For example. class MyClass { //this is a normal constructor public MyClass(){ //do something } //this is a parameterized constructor public MyClass(int var){ //do something } //this is another parameterized constructor public MyClass(String var, Integer var2){ //do something } }


Like methods, constructors can also be overloaded. Since the constructors in a class all have the same name as the class, their signatures are differentiated by their parameters lists


When the programmer has not coded a constructor for any java class.


When any constructor is deffined in your class, the java compiler create a default no argument constructor for you. This constructor only have an invocation to the super class constructor (" super( ) ").


All Java programs would have a constructor... public class Test { public Test(){ ... } ..... } This is a constructor. Even if you dont code the constructor Java would automatically place a default constructor for compilation.


A constructor is just a special form of a method. You can overload constructors in the exact same way as you can overload any other method.


What are the importance of constructor in java? Constructor is automatically called immediately after the object is created , before the new operator complete . Constructor is important because they have no return type , not even void.


No. The constructor is the starting point of creation of any object in Java. Without going through a constructor you cannot create an object


Constructor is used to do something (written in constructor) immediately after object creation.



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