'Copper loss' (I2R losses) is the generic term to describe energy losses that occur in any conductor (windings, in the case of Transformers and other machines). The term applies, even when the conductors are manufactured from aluminium or other metals. The losses occur due to the temperature difference beween the conductor and the surrounds, causing heat transfer away from the conductor.
The iron losses can be minimized by annealing the steel. ask any other questions about DC/AC 3 phase motors. (Noumankhalid@ymail.com)
Power transformers have both no load and full load losses. The key is copper wiring, as copper varies with the square inches of the secondary and primary currents.
The frictional losses and the resistive losses generate heat in a motor
Copper losses are energy losses from the windings, due to the currents passing through them. During an open-circuit test, there is no secondary current (so no secondary copper losses) and the primary current is very low (so the primary copper losses are minimum).
because of its losses i.e iron and copper losses. since iron loss depends on voltage (v)and copper loss depends on current(i).
Yes you can turn a motor into a generator, if it is a permanent magnet motor.
Copper is not something that is calculated. The amount of copper might be, or copper losses / load losses, might be, but "copper" is not calculated.
how to reduce copper losses in a transformer Copper losses are due to the resistance of the copper (or aluminum) windings. To reduce copper losses the transformer would have to be rewound with heavier gage wire.
copper losses are power losses due to flow of current in the wires or resistances,if the resistance is R, current is I then copper losses are I2R. for a 3-phase system; copper losses are same but for a single line, total losses are 3I2R.
Copper losses are also referred to as I^2 R losses. Copper loss is due to heating due to the current passing through the copper windings.
reactive power depends on motor winding losses and the reason for increasing of temperature. At running condition the motor power reduces by copper loss.
Copper losses are purely voltage-drop losses (I squared R) caused by the resistance of the windings, as opposed to hysteresis losses and eddy current losses (so-called iron losses), which are magnetic in nature. They are called copper losses whether the winding conductors are made of copper or not, by the way.
Yes, the output line used to find the losses, usually for smaller machines we take copper losses equal to the iron losses.
The input power, Pin, is reduced by different loss sources in the system. These reductions are the difference between input power & output power. The losses are: PSCL: Stator copper losses, or I2R losses Pcore: Core losses PRCL: Rotor copper losses PF&W: Friction & windage losses Pmisc: miscellaneous losses All of these losses reduce the input power. The output power is the input power minus all of the losses. Pout = Pin - PSCL - Pcore - PRCL - PF&W - Pmisc
Power transformers have both no load and full load losses. The key is copper wiring, as copper varies with the square inches of the secondary and primary currents.
how much copper in 250 hp motor
Yes, Motor oil will not damage copper.
The frictional losses and the resistive losses generate heat in a motor