3,35 moles of acetone is equal to 194,57 g.
about .00099 Pa-s
This is a density problem. Density = mass/volume. As long as we know two of the variables, we can solve for the missing variable. The density of acetone is 0.791g/mL at 25ºC.Known/Given:volume of acetone= 28.62mLdensity of acetone at 25oC = 0.791g/mLUnknown:mass of acetoneFormula:density = mass/volumeSolve for mass:density x volume = mass0.791g/mL x 28.62mL = 22.6g
What is the volume, In millimeter of 6.68 g of acetone ?
Acetone has the molecular formula of CH3COCH3 (C3H6O) and a molar mass of 58.08 g/mol.
Density of acetone (liquid) is 0.7845 g cm−3 (25 °C)
8.40G is the value in mL of 6.60g of acetone if the density is 7857.
3,35 moles of acetone is equal to 194,57 g.
To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.
Density is the quantity of matter present in a unit of volume. It is denoted by D. The SI unit for density is kg/m^3. The density of acetone vapour is 0.86 kg/m^3 at 98.5 degree Celsius.
about .00099 Pa-s
The density acetone is 0.79 g/cm3. So 12 cm3 has a mass of 9.48 g
At 84°C it would be a vapor because its higher then 56.2°C and the acetone will evaporate
This is a density problem. Density = mass/volume. As long as we know two of the variables, we can solve for the missing variable. The density of acetone is 0.791g/mL at 25ºC.Known/Given:volume of acetone= 28.62mLdensity of acetone at 25oC = 0.791g/mLUnknown:mass of acetoneFormula:density = mass/volumeSolve for mass:density x volume = mass0.791g/mL x 28.62mL = 22.6g
What is the volume, In millimeter of 6.68 g of acetone ?
Acetone has the molecular formula of CH3COCH3 (C3H6O) and a molar mass of 58.08 g/mol.
With a density of 0.7857g/cm3, you have a mass of 13.78mL.