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Density of acetone (liquid) is 0.7845 g cm−3 (25 °C)
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What is density of acetone at 23 c?
The density of acetone at 23°C is approximately 0.7845 g/cm^3.
What is the value in mL of 6.60g of acetone if the density is 7857?
To find the volume in mL, divide the mass of acetone by its density. Volume = mass / density = 6.60g / 7857 g/mL ≈ 0.00084 mL. Therefore, 6.60g of acetone has a volume of approximately 0.00084 mL.
How convert 1kg of acetone to liters?
To convert 1 kg of acetone to liters, you need to know the density of acetone. The density of acetone is around 0.791 kg per liter at room temperature, so 1 kg of acetone would be approximately 1.27 liters.
What is the volume in milliliters of 6.76g of acetone?
To calculate the volume of a substance, you need to know its density. The density of acetone is approximately 0.79 g/mL. By dividing the mass (6.76g) by the density (0.79g/mL), you can find that the volume of 6.76g of acetone is approximately 8.56mL.
What is the mass in grams of 28.40mL of acetone?
To find the mass of acetone, we need to know the density of acetone, which is 0.786 g/mL. Multiplying the volume (28.40 mL) by the density gives us the mass of acetone: 28.40 mL * 0.786 g/mL = 22.33 grams.
What is the volume of 85.1g of acetone?
To find the volume of acetone, we need to know its density. The density of acetone is around 0.79 g/cm^3. Using the formula Volume = Mass / Density, the volume of 85.1g of acetone would be 107.84 cm^3.
What is the mass in grams of 17.54mL of acetone?
You need to konw the density of acetone (propanone) The use the equation density = mass / volume d = m/v m = dv
What is the mass in grams of 28.62mL of acetone?
This is a density problem. Density = mass/volume. As long as we know two of the variables, we can solve for the missing variable. The density of acetone is 0.791g/mL at 25ºC.Known/Given:volume of acetone= 28.62mLdensity of acetone at 25oC = 0.791g/mLUnknown:mass of acetoneFormula:density = mass/volumeSolve for mass:density x volume = mass0.791g/mL x 28.62mL = 22.6g
What is the volume in ml of 6.54 g of acetone?
To find the volume of a substance, you would need to know its density. The density of acetone is approximately 0.79 g/mL. Using this information, you can calculate the volume of 6.54 g of acetone by dividing the mass by the density (6.54 g / 0.79 g/mL = 8.27 mL).
What is the Volume of 10 grams of acetone?
To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.
What is the density of acetone vapour at 98.5 degree Celsius?
Density is the quantity of matter present in a unit of volume. It is denoted by D. The SI unit for density is kg/m^3. The density of acetone vapour is 0.86 kg/m^3 at 98.5 degree Celsius.
How much acetone (CH3COCH3) would be needed to obtain 3.35 moles of acetone The density of acetone is 0.851 gmL.?
To calculate the amount of acetone needed, we first need to find the molar mass of acetone, which is approximately 58.08 g/mol. Then, we can use the density to convert moles to grams: 3.35 moles * 58.08 g/mol = approximately 194.788 g. Finally, we can convert grams to volume using the density: 194.788 g / 0.851 g/mL ≈ 228.91 mL of acetone would be needed.
