CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
Empirical formula (lowest whole number) for C4H8 is CH2, obtained by dividing by 4.
C = 12H = 1 x 2 = 2-----------------total = 14 g/mole for empirical56.11/14 = 4.00 so there are 4 empirical formulae in 56.11 gChemical formula = C4H8
No, because both propane (C3H8) and butene (C4H8) have the same empirical formula (CH4), which is the simplest ratio of the elements present in the compound. To differentiate between propane and butene, one would need additional information such as molecular formula or structural information.
Well you know that Butanoic Acid's Molecular formula is C3H7COOH, and Empirical formula is a compound showig the simplest ratio of numbers of atoms of each element in the compound. Now the question is, can you simply C3H7COOH ? Nope! Then the Empirical formula is also C3H7COOH
C4H10 is the molecular formula for butane, as it represents the actual number of atoms of each element in a single molecule of the compound. The empirical formula for butane would be CH5, as it shows the simplest whole number ratio of atoms present in the compound.
C12h24
It is an empirical formula.
CH will be the empirical formula and C12H12 will be the molecular formula
A formula unit is an empirical formula.
It has a molecular formula of C10H8 so that would make an empirical formula of C5H4.
In this instance, the empirical formula is the same as the formula unit: NaNO3