CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
C4H10 is the molecular formula for butane, as it represents the actual number of atoms of each element in a single molecule of the compound. The empirical formula for butane would be CH5, as it shows the simplest whole number ratio of atoms present in the compound.
C12h24
C = 12H = 1 x 2 = 2-----------------total = 14 g/mole for empirical56.11/14 = 4.00 so there are 4 empirical formulae in 56.11 gChemical formula = C4H8
No, because both propane (C3H8) and butene (C4H8) have the same empirical formula (CH4), which is the simplest ratio of the elements present in the compound. To differentiate between propane and butene, one would need additional information such as molecular formula or structural information.
Well you know that Butanoic Acid's Molecular formula is C3H7COOH, and Empirical formula is a compound showig the simplest ratio of numbers of atoms of each element in the compound. Now the question is, can you simply C3H7COOH ? Nope! Then the Empirical formula is also C3H7COOH
Empirical formula (lowest whole number) for C4H8 is CH2, obtained by dividing by 4.
CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
C4H10 is the molecular formula for butane, as it represents the actual number of atoms of each element in a single molecule of the compound. The empirical formula for butane would be CH5, as it shows the simplest whole number ratio of atoms present in the compound.
C12h24
C = 12H = 1 x 2 = 2-----------------total = 14 g/mole for empirical56.11/14 = 4.00 so there are 4 empirical formulae in 56.11 gChemical formula = C4H8
C2h4, c3h6, c4h8
No, because both propane (C3H8) and butene (C4H8) have the same empirical formula (CH4), which is the simplest ratio of the elements present in the compound. To differentiate between propane and butene, one would need additional information such as molecular formula or structural information.
Yes, if you have some additional information, such as the molecular weight. For instance, the molecules C2H4 and C4H8 have exactly the same percent composition, but they are very different molecules. So you need some other information to tell them apart than the percent composition.Answer ExpandedThis is kind of a trick question. By knowing the percent composition, you would easily be able to determine its empirical formula, but molecular formula is a bit different. The molecular formula is the actual number of atoms in a molecule, so in order to find the specific molecular formula of a substance, you would also need to know how many grams there is of that substance.(This explains the difference between C2H4 and C4H8)
Well you know that Butanoic Acid's Molecular formula is C3H7COOH, and Empirical formula is a compound showig the simplest ratio of numbers of atoms of each element in the compound. Now the question is, can you simply C3H7COOH ? Nope! Then the Empirical formula is also C3H7COOH
* For the alkanes, the general formula is CnH2n+2 EXAMPLE: CH4, C4H10 * For the alkenes, the equation is CnH2n EXAMPLE: C2H4 where n is the number of atoms in one molecule of the hydrocarbon.
C4H8 can refer to either an alkene or an alkane. In the case of an alkene, it would be 1-butene, while for an alkane, it would be 2-methylpropene. The distinction can be made based on the presence of a double bond in the alkene.
C4H8 can refer to two different organic compounds: butene and butane. Butene is a linear alkene with four carbon atoms, while butane is a straight-chain alkane. So, C4H8 can be both butane and butene, depending on the specific structure.