Fe2O3 is just a compound of iron and oxygen it is also known as rust
FeSO4 =Fe2O3 +So2 +SO3
3h2so4+fe203------>fe2(H2So4)3 + H20 conc.
physical
mechanical nuclear chemical physical
Iron (Fe), 26 electrons in neutral atom, 23 in Fe3+. Rust, Fe203 has Fe3+ ions.
With what to do what? If you just mean with any other element, it can be combined with any other element. Fe203 (rust) H20 (water) those are examples of oxygen combining with iron and hydrogen to form those 2 compounds
in one molecule of Fe2O3 there would be 3 oxygen atoms
First you add OH to H2O which makes Fe203. Next you will have to subtract that by the FE which leaves you with 2O3. Finally add that up with 2O3 and equal. 2 Fe(OH)3 = 3 H2O + Fe2O3
This one Akadama soil composition defined. Akadama soil: Al203 0.334 kg kg−1, SiO2 0.470 kg kg−1, Fe203 0.157 kg kg−1 by weight. See link: http://onlinelibrary.wiley.com/doi/10.1111/j.1747-0765.2006.032_6.x/abstract
First of all rust is formed when iron is exposed to both oxygen and water/ water vapopurs. The formula for rust is Fe203.xH20. Now the x varies which determines the extent to which rust is formed. Basically Rust is formed throughout the surface of the iron thus preventing rusting of the inner layers.
The name of that compound is Iron (III) Oxide. The reason you must include the "(III)" is because Iron (Fe) has two possible charges, 2+ and 3+. If it was Iron (II) Oxide, the formula would be FeO. This is because Iron would have a 2+ charge, and the Oxygen would have a 2- charge, so it would bond equally.