Q: What is full from of l l b?

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Surface area of cuboid = 2*[L*B + B*H + H*L] where L = length, B = breadth, and H = height

The surface area of a cuboid is 2*(L*B + B*H + H*L) where L = length, B = breadth and H = height. In a cube, L = B = H and so surface area = 6*L2

There are infinitely many such rectangles.Consider any positive number, B which is less than 6 gronks. Let L be 12-B gronnks. Then L > 6 and so no ordered pairs (L, B) will be equal to a (B, L).Any rectangle with length L gronks and breadth B gronks will have a perimeter of 2*(L+B) = 2*12 = 24 gronks.Since the choice of B was arbitrary there are infinitely many choices for B and since each value of B gives a unique rectangle, there are infinitely many rectangles.As many as you want.

Total surface area = 2*(L*B + B*H + H*L) square units where L = length, B = breadth and H = height.

Use Pythagoras l^2 = a^2 + b^2 A = (7,9) & B= (3,12) NB 'A' & 'B' are NOT the same as 'a' & 'b' . Each is just a label, Hence l^2 = (7-3)^2 + (9 - 12)^2 l^2 = 4^2 + (-3)^2 l^2 = 16 + 9 l^2 = 25 l = sqrt(25) l = 5 The answer!!!!!

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Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2

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Suppose the length is L and the breadth is B. Then since perimeter = 58, 2*(L+B) = 58 so that L+B = 29 that is L = 29-B Now Area = L*B = 204 That is (29-B)*B = 204 Or B2 - 29B + 204 = 0 which is equivalent to (B-12)*(B-17) = 0 So, using L+B = 29, L and B are 12 and 17.

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it's possible press a,up,b,left,right,a,a,a,a,b,b,b,b,b,b everything is on the controls now press r,r,r,r,r,l,l,l,l,l,a,b,up,down,l,r,right,left to get unlimited master balls