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Q: What is full load current of 3hp motor?
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What is the full load running current of a 3hp 208volt single phase continuous duty ac motor?

It would probably be 20-30 amps. <<>> The electrical code book states a value of 18.7amps for a 3HP 208 volt motor. If the nameplate data is available it is always best to use it when calculating wire size and overload protection for the motor.


How do you find the no load amp rating of a motor?

Full load amps is found on the motor's nameplate, and is unique to that particular brand and model number. A Magnetec 2hp motor will draw different amps than a Baldor 2hp, etc. There are high efficiency motors, and not so high as well. Consult the nameplate. If you want a "rule of thumb" to estimate the RLA (Running Load Amps - this is the term most often found on the nameplate - same as full load amps), then use this: Figure about 1400 watts per horsepower. Divide Watts by volts to get Amps, for example: * 3hp motor, 120V * 3hp X 1400 W = 4200 W * 4200 W / 120 V = 35 A This formula is only for single-phase motors! I looked up a typical 3hp 120 V Baldor motor in the Grainger's catalog, and the RLA for it was 32.0, so this will get you in the ballpark. I have seen 3hp 120 V motors as low as 25 A and as high as 40, so DO NOT use the rule of thumb to size branch circuit conductors or overcurrent protection! For 3-phase motors: Figure about 1100 watts per horsepower (3-phase is a little more efficient). Divide Watts by Volts, then divide the answer by 1.73 to get Amps, for example: * 3hp motor, 208V 3Ph * 3hp X 1100 W = 3300 W * 3300 W / 208 V = 15.86 * 15.86 / 1.73 = 9.16 A This formula is only for 3-phase motors! My Grainger's catalog motor with the same Voltage and HP had a nameplate rating of 8.34 A.


How do you calculate the power consumption of 3 phase 2.2 kW induction motor drawing 3A current at 400 volts and 0.9 PF?

The power consumed can be calculated directly from the current draw, voltage, and power factor: (3A) x (400v line to line) x (sqrt(3)) x (.9pf) = 1.87kW. This would be a reasonable value for a 3hp motor that is not running under full load (the motor may be slightly over-sized for this application). The size of the motor is irrelevant to this calculation, although it shows that it is running at ~85% of its capability.Another AnswerSince a motor is a balanced load, we use the following equation to find its input power:power = 1.732 x line voltage x line current x power factor.So, in your example,power = 1.732 x 400 x 3 x 0.9 = 1870 WObviously, it cannot be delivering 2200 W when its input is just 1870 W. However, to determine its output power you will need to determine its efficiency at that input.


How much current will a 5 hp 1 phase 120V motor pull?

The largest 120V motor generally available is 3hp. A 3hp, 120V motor draws about 30 amperes. All true 5hp motors I have seen are 230V or higher. Note that some motors, such as compressors and vacuum cleaners, use artificially high hp numbers to entice you to buy their unit (they will use terms like peak-developed hp, etc.). These ratings are not true hp, and you just have to go by the nameplate rating on the unit. For instance, I have a Sanborn Air Compressor that claims 4 PEAK horsepower, yet only draws 17 amperes at 120V. Its really closer to a 2hp motor.


How many watts does a 240 volt 5 hp motor use?

If you are asking about an actual motor it is best to read the motor's rating plate. If you are asking how to figure out the current in Amps drawn by a motor which produces a power output of 3 horsepower (hp) this question is way too vague to be answered accurately without knowing a lot more technical details. The current drawn will depend on (a) the type of motor and (b) the Voltage that the motor is designed to run on. Regarding motor type, is it a Direct Current motor or, if it is an Alternating Current motor, is it a single-phase motor or a 3-phase motor. If it is a single-phase motor, then is it a squirrel-cage induction motor or a commutator motor of the type often used in vacuum cleaners or power tools? Another type of alternating current motor is the slip-ring synchronous motor but that type is not often used to supply only 3 horsepower. A very rough way to calculate a possible current draw if you know the motor's operating voltage is to use the fact that 1 hp is approximately equal to 0.75 kiloWatts. So 3 hp = 3 x 0.75 = 2.25 kW. Now, knowing that the actual efficiency of a motor depends entirely upon its design type, we shall have to assume an efficiency factor for the conversion of electrical power to mechanical power. If we assume the motor is only 50% efficient then, to produce 3 hp, it will have to be supplied with electrical power of at least 2 x 2.25 = 4.5 kW. Since Power P (Watts) = V (Volts) x I (Current in Amps), the current drawn I would therefore be given by I= P/V: At 12 Volts DC: 4,500 / 12 = 375 Amps. (This would be a typical peak starting current drawn by, say, the starter motor of a small car engine in Summer. In Winter it might get to 500 Amps or more!) At 120 Volts RMS AC: 4,500 / 120 = 37.5 Amps RMS single phase At 240 Volts RMS AC: 4,500 / 240 = 18.75 Amps RMS single phase

Related questions

What is the full load running current of a 3hp 208volt single phase continuous duty ac motor?

It would probably be 20-30 amps. <<>> The electrical code book states a value of 18.7amps for a 3HP 208 volt motor. If the nameplate data is available it is always best to use it when calculating wire size and overload protection for the motor.


Is there a difference in a Johnson 3hp motor and a Johnson 3hp seahorse?

i gota three 3hp seahorse johnson boat motor i need to get to head how does everthing come apart


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How do you find the no load amp rating of a motor?

Full load amps is found on the motor's nameplate, and is unique to that particular brand and model number. A Magnetec 2hp motor will draw different amps than a Baldor 2hp, etc. There are high efficiency motors, and not so high as well. Consult the nameplate. If you want a "rule of thumb" to estimate the RLA (Running Load Amps - this is the term most often found on the nameplate - same as full load amps), then use this: Figure about 1400 watts per horsepower. Divide Watts by volts to get Amps, for example: * 3hp motor, 120V * 3hp X 1400 W = 4200 W * 4200 W / 120 V = 35 A This formula is only for single-phase motors! I looked up a typical 3hp 120 V Baldor motor in the Grainger's catalog, and the RLA for it was 32.0, so this will get you in the ballpark. I have seen 3hp 120 V motors as low as 25 A and as high as 40, so DO NOT use the rule of thumb to size branch circuit conductors or overcurrent protection! For 3-phase motors: Figure about 1100 watts per horsepower (3-phase is a little more efficient). Divide Watts by Volts, then divide the answer by 1.73 to get Amps, for example: * 3hp motor, 208V 3Ph * 3hp X 1100 W = 3300 W * 3300 W / 208 V = 15.86 * 15.86 / 1.73 = 9.16 A This formula is only for 3-phase motors! My Grainger's catalog motor with the same Voltage and HP had a nameplate rating of 8.34 A.


What is the correct spark plug for 1968 3hp 2cyl Johnson outboard motor?

David Underhay The decal on my 1968 3hp Johnson says use either of: Champion J4J, AC M42K, Autolite A21X sparkplugs. You may have to find the current equivalents


What is the spark plug gap for a 1993 3hp evinrude outboard motor?

The recommended plug gap for the 1993 model, 3hp Evinrude outboard is .030 in.


What year evinrude motor serial number 3014--02070?

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Do 1 phase electric motors need starters?

it depends on the load and size of the motor if the motor has to drive heavy loads from initial state it require more torque, for this we use star-delta starters where load on motor in permissible then we use a DOL starters DOL starters are direct supply feeders to the motor so there is no rule to use a starter. we can use anything to swith the motor. for protection we need a overload relay and you ask for a 1ph motor, i.e maximum 3hp motors are available for less than 2 hp motor you can use a 6amp switch used in household or a 6amp mcb (includes overload). for 3hp a 16 amp switch or a 10amp mcb is more than enough


How do you calculate the power consumption of 3 phase 2.2 kW induction motor drawing 3A current at 400 volts and 0.9 PF?

The power consumed can be calculated directly from the current draw, voltage, and power factor: (3A) x (400v line to line) x (sqrt(3)) x (.9pf) = 1.87kW. This would be a reasonable value for a 3hp motor that is not running under full load (the motor may be slightly over-sized for this application). The size of the motor is irrelevant to this calculation, although it shows that it is running at ~85% of its capability.Another AnswerSince a motor is a balanced load, we use the following equation to find its input power:power = 1.732 x line voltage x line current x power factor.So, in your example,power = 1.732 x 400 x 3 x 0.9 = 1870 WObviously, it cannot be delivering 2200 W when its input is just 1870 W. However, to determine its output power you will need to determine its efficiency at that input.


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My daughters mini bike with a 3hp Briggs has 80psi compression and runs great. A motor I got "running" off eBay has 55psi compression, runs but has NO power. -Jason


Why does my 3hp Briggs and stratton motor clutch slip how do you stop it?

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