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Transfer function is the relationship between output and input of a circuit. In the clipping circuit, the general transfer function is such that the transfer curve Av is less than 1 for passive limiter and greater than 0 to limit the maximum and minimum voltage value.
The Unijunction emitter current vs voltage characteristic curve figure(a) shows that as VE increases, current IE increases up IP at the peak point. Beyond the peak point, current increases as voltage decreases in the negative resistance region. The voltage reaches a minimum at the valley point. The resistance of RB1, the saturation resistance is lowest at the valley point.Ip and Iv, are datasheet parameters; For a 2n2647, IPpand IVvare 2µA and 4mA, respectively. Vp is the voltage drop across RB1 plus a 0.7V diode drop; see Figure (b). Vv is estimated to be approximately 10% of VBB.
basically a diode flows an exponential curve Vs current if you try to double the voltage drop by increasing the voltage it should self destruct
A: Both diodes have the same curve in the forward direction however if the zener voltage is reverse it will breakdown at a particular voltage and remain conducting at the voltage. A regular diode will not do that the to voltage will fold back after breakdown to any voltage
when we look at the curve ,, we can see that before the peak point curve has greater slope as compared to the slope after the peak point .. the reason is PL is given as I^2RL ,,, current is a squared term here . before peak point current is greater so overall change in power is much greater but after peak point RL is greater and current is less now the load resistance is not a squared term... so slope will be less. therefore the curve is not symetrical
It moves side ways
explain what happens inside curve sample
Transfer function is the relationship between output and input of a circuit. In the clipping circuit, the general transfer function is such that the transfer curve Av is less than 1 for passive limiter and greater than 0 to limit the maximum and minimum voltage value.
Explain the consumer equilibrium with the help of indifference curve?
no
example of a J-curve population in nature? Explain.
How do you draw the total product Curve:
The Unijunction emitter current vs voltage characteristic curve figure(a) shows that as VE increases, current IE increases up IP at the peak point. Beyond the peak point, current increases as voltage decreases in the negative resistance region. The voltage reaches a minimum at the valley point. The resistance of RB1, the saturation resistance is lowest at the valley point.Ip and Iv, are datasheet parameters; For a 2n2647, IPpand IVvare 2µA and 4mA, respectively. Vp is the voltage drop across RB1 plus a 0.7V diode drop; see Figure (b). Vv is estimated to be approximately 10% of VBB.
This is because if a marginal figure is less than an average figure, the new average figure will decrease.
explain graphically the movement along the demand curve
Its the same I think :)
A 3-dimensional figure. It need not be solid since it could be a curve in 3-d space.A 3-dimensional figure. It need not be solid since it could be a curve in 3-d space.A 3-dimensional figure. It need not be solid since it could be a curve in 3-d space.A 3-dimensional figure. It need not be solid since it could be a curve in 3-d space.