1/3 of the initial volume (Boyle-Mariotte law).
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
half
PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT
For a gas, pressure and volume are inversely related. If pressure decreases, volume will increase.
It would be half of the original volume. As you reduce the volume the pressure would increase and at half the original volume the pressure would be doubled.
PV=RT, if the volume is tripled at constant temperature, the pressure drops to one third.
Because of your mom
Temperature will be increase
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
As a consequence of Boyle-Mariotte law: 166 cm3.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The equation is P1V1=P2V2. (P1 is pressure before the change, P2 is the pressure after, V1 is the volume before the change, and V2 is the volume after it.) So to solve it, it would be the same change no matter how much the volume and pressure were to begin with. The values are P1= 1 atmosphere (the pressure of air at sea level) V1= 1 Liter which would mean P2=3 atmospheres 1*1=3(V2) 1/3 Liter= V2. So the volume would be one third of what it was before the pressure was tripled.
From Boyle's law pressure (P) times volume (V) divided by temperature T is a constant; so if T is held constant then if pressure triples volume is decreased to 1/3 its original value
A [multiplicative] change in one dimension makes the same change in the volume. So the volume would be tripled.
half
PV=nRT If n,R,T are constant than the only thing that can change is P 3*V has to be cancelled out 1/3 * 3 = 1 1/3P * 3V = nRT