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ka=[H+][NO2_]/[HNO2]
Ka= [H+][NO2-] [HNO2]
not sure
Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
Ka= [h+][HCO3-]/[H2CO3]
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
3.4 * 10^-8
ka=[H+][NO2_]/[HNO2]
Ka= [H+][NO2-] [HNO2]
not sure
Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
Ka= [h+][HCO3-]/[H2CO3]
ka=[H+][NO2_]/[HNO2]
6.6 x 10-9
ka=[H+][CN-]/[HCN]
Since H3PO4 has 3 ionizable hydrogens, it will have three Ka values. Approximate values areKa1 = 7x10^-3; Ka2 = 6x10^-8 and Ka3 = 4.5x10^-13
putang ina mo gaguu ka wag ka na secreto lang 2