lemda is the symbol which is used ij modern physics for wavelength.It is measured in metres asit is the distance travelled among light
As lemda{max} T = constant = 2898 u m K lemda{max} = 2898 u m K / T lemda{max} = 2898 u m K / 3OOk lemda{max} = 2898 u m K / 3OO lemda{max} = 9.66 u m in infrared region
Can you give the context, that is the type of situation or measurement involved.
1 over lemda2 pie over lemda
as v=f/\(lemda), it shows that velocity dependx on the frequency of wave i.e numbr of wavs produced in one second and wavelength(lemda) which is the distance between two consecutive crests or troughs in transverse waves nd in longitudnal waves it is distance betwen two consecutive compressions or rarefactions.
At the point of contact the lens and the glass plate, the thickness of the film is effectively zero but due to reflection at the lower surface of air film from denser medium, an additional path difference of Lemda/2 is introduced. consequently, the centre of newton ring is dark due to destructive interference.