The this pointer is a hidden argument that is automatically generated by the compiler to refer to the current instance of an object.
Consider the following snippet:
class foo{};
void bar(foo* f){
std::cout< } int main() { foo f; bar(&f); return(0); } The function, bar, knows which instance of foo it is working on because we must explicitly pass a pointer to that instance (the address of f). However, if bar were a member of foo, we do not need to pass a pointer to the instance because the compiler does it automatically for us: class foo { void bar(){std::cout< }; int main() { foo f; f.bar(); return(0); } Although the second example is what we would physically write, it's really just sugar-coating. Behind the Scenes, it's as if bar() were a non-member function and is actually implemented as per the first example, where we passed the address of the instance into the function. This is because there is only ever one instance of the bar function (regardless of how many instances of foo we create), and the compiler needs some way of determining which instance of foo the bar function should work with -- thus it generates a this pointer for us and hides the actual implementation behind sugar-coated code. The hidden this pointer is also used implicitly (behind the scenes) whenever you call member methods from within other member methods of the same class. However, you can invoke methods explicitly by dereferencing the this pointer if you want to. For instance, to invoke the bar() method from within another method of foo, you'd use the following call: (*this).bar(); More typically, you'd use the points-to operator instead: this->bar(); But since the this pointer is implicit, you don't need to explicitly dereference members like this unless it helps to clarify your code (such as when a member method operates upon other instances of the same class, and specifying this helps to clarify exactly which members you are invoking upon which instances). However, the this pointer really comes into its own when you actually need to refer to the current instance, such as when performing self-reference checks and returning references to the current instance. A classic example is the assignment operator which typically requires both: class foo { public: foo& operator=(const foo& rhs) { if( this != &rhs ) { // perform assignment } return(*this); } };
The pointer that points to a block of memory that does not exist is called a dazzling pointer or wild pointer
An address in C or C++ is the location in memory of an object or function. An address is the contents of a pointer, as opposed to the contents of the memory location pointed to by the pointer.
println is not a C++ keyword.
An asterisk in C++, such as int *data, is what's known as a pointer. A pointer is like a regular variable, but instead of holding a value, a pointer holds the memory location of the value. It's a somewhat difficult concept, and you can learn more about it here: See related links section below...
Yes, C++ has pointers, which are references to memory locations. which are variables that store memory addresses, or NULL (zero). If the pointer is non-NULL, the pointer is said to dereference the object (or variable) residing at the stored memory address, which permits indirect access to that object so long as the object remains in scope.
The pointer that points to a block of memory that does not exist is called a dazzling pointer or wild pointer
Address of the current object.
Pointer is like variable address the members in memory shell
a pointer that is not pointing to anything
An address in C or C++ is the location in memory of an object or function. An address is the contents of a pointer, as opposed to the contents of the memory location pointed to by the pointer.
Multiplication is yet another thing, what you should never do with pointers.
The function ftell returns the position of the file pointer for a file.
println is not a C++ keyword.
Yes. All string variables are pointers as are other arrays.
An asterisk in C++, such as int *data, is what's known as a pointer. A pointer is like a regular variable, but instead of holding a value, a pointer holds the memory location of the value. It's a somewhat difficult concept, and you can learn more about it here: See related links section below...
Example: void foo( MyClass& object ){} // function with call by reference signature MyClass* p = new MyClass(); // instantiate a pointer to MyClass foo( *p ); // call by reference using the pointer
Yes. If the ports are memory mapped, then you simply need a pointer to that address, and you need to declare the pointer as volatile. If they are I/O mapped, then you need to create an _asm{} block.