acceleration
You apply a force to the object.You apply a force to the object.You apply a force to the object.You apply a force to the object.
the force you apply to a simple machine is force
By exchanging for for distance. You need to apply less force, but you need to apply it over a larger distance. Since work (or energy transfer) is force x distance, the total work is the same.
As a simplified explanation, work = force x distance. You need to apply a force over a certain distance, for work to be done.
acceleration
You apply a force to the object.You apply a force to the object.You apply a force to the object.You apply a force to the object.
the force you apply to a simple machine is force
By exchanging for for distance. You need to apply less force, but you need to apply it over a larger distance. Since work (or energy transfer) is force x distance, the total work is the same.
As a simplified explanation, work = force x distance. You need to apply a force over a certain distance, for work to be done.
Basically, the longer the handle, the less force is needed to apply a certain torque. This is defined by the equation t=fd where t= torque, f= force, and d= distance in a radial fashion.
If there be no force ie no deceleration then no need to apply any force to compensate such a deceleration. But deceleration is there due to frictional force between the tyre and the road. Hence to compensate this we have apply acceleration. So force is needed OK Physics laws State that an object in motion will remain in motion until acted upon by an outside force. The car moving at a constant speed is being acted upon by wind resistance, gravity, and friction. Therefore force is needed to retain the constant speed
Yes. Erosion is weathering. It's can apply force but doesn't have to.
What are the requirements needed to apply for a job?
a reaction force
If you apply it at the top of the barrel, it's horizontal component needs to be opposite to and with greater magnitude than static friction. If you apply the force on some other spot with vertical distance d from the center of rotation the horizontal component of the force you need to apply is F=-1.5*T*R/(2d+R) where T is the friction and R the radius of the barrel.
A force is needed to move an object.