The net ionic equation for formation of a precipitate [note correct spelling] when sodium sulfate and barium chloride solutions are mixed is Ba+2 + SO4 -2 -> BaSO4 (s)
CuSO4 + BaCl2 --> CuCl2 + BaSO4
(NH4)2SO4(aq) + BaCl2(aq) → 2NH4Cl(aq) + BaSO4(s). Barium sulfate is the precipitate.
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
barium choride and calcium sulphate will form
89.3
Barium chloride can be precipitated wit a sulfate; barium sulfate is then filtrated.
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
There is no equation in the question, only two pair of two reactants.
Copper nitrate and barium chloride do not react. Barium chloride solution produces a white precipitate with solutions containing sulfate ions.
The formula unit for the formation of potassium chloride and barium sulfate is one mole. One unit of potassium sulfate and barium chloride are required for the reaction.
The equation is:Ba+ + (SO4)2- = BaSO4(s)
CuSO4 + BaCl2 --> CuCl2 + BaSO4
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.
add water to dissolve the sodium chloride, filter and you can collect the barium sulfate behind the filter paper
BaCl2+K2SO4=2KCl+BaSO4
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
BaSO4 + 2CaCl2 --> Ba(Cl2)2 + Ca2SO4