barium choride and calcium sulphate will form
Au(III)SO4,BaSO4
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
Yes.
calcium chloride and water
when barium chloride reacts with copper sulphate a double dispacement resction takes place,where: BaCl2(aq) + CuSO4(aq) --> BaSO4(s) + CuCl2(aq) The ionic equation is more descriptive: Ba2+ + 2Cl- + Cu2+ + SO4^2- --> BaSO4(s) + Cu2+ + 2Cl- The net ionic equation tells us that barium ions will always react with sulfate ions to make an insoluble product. Ba2+ + SO4^2- --> BaSO4(s)
There is no equation in the question, only two pair of two reactants.
BaSO4 + 2CaCl2 --> Ba(Cl2)2 + Ca2SO4
The insoluble salt barium sulfate is obtained.
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
Au(III)SO4,BaSO4
BaCl2+K2SO4=2KCl+BaSO4
Barium sulfate is much less soluble in water than either of sodium chloride and sodium chloride. When mixed, the solubility of the barium sulfate is exceeded. The barium sulfate then precipitates as fine solids, which remain suspended but scatter light to produce the milky look. Added: Na+ (sodium ion) and Cl- (chloride ion) don't react, Only Ba2+ and SO42- do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
barium chloride plus sodium sulphate yields barium sulphate plus sodium chloride
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
Barium chloride; BaCl2
Barium chloride: BaCl2