barium choride and calcium sulphate will form
When gold(III) sulfate and barium chloride react, a double displacement reaction occurs. The products are barium sulfate (a white solid) and gold(III) chloride. Gold(III) chloride is a yellow solid that is sparingly soluble in water.
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
The balanced chemical equation for Barium chloride plus Aluminium sulphate gives Barium sulphate Aluminium chloride is represented as .3BaCl2(aq) + Al2(SO4)3(aq) --> 3BaSO4(ppt) + 2AlCl3(aq).The ppt formed are white in color.
The ionic equation for barium chloride (BaCl2) plus copper sulfate (CuSO4) is Ba2+ + SO4^2- → BaSO4(s) and Cu2+ + 2Cl- → CuCl2. This suggests the formation of a white precipitate of barium sulfate and copper chloride in solution.
Barium Cholride and sulphuric acid create a white precipitate, videos of the reaction is on this website http://jchemed.chem.wisc.edu/jcesoft/CCA/CCA4/MAIN/BACL/PAGE1.HTM
This word equation is incorrect because it does not follow the law of conservation of mass. The equation should be: calcium chloride plus magnesium sulfate yields barium sulfate plus magnesium chloride.
The balanced equation for the reaction between barium sulfate (BaSO4) and calcium chloride (CaCl2) is BaSO4 + CaCl2 -> BaCl2 + CaSO4. This reaction forms barium chloride (BaCl2) and calcium sulfate (CaSO4) as products.
The insoluble salt barium sulfate is obtained.
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
When gold(III) sulfate and barium chloride react, a double displacement reaction occurs. The products are barium sulfate (a white solid) and gold(III) chloride. Gold(III) chloride is a yellow solid that is sparingly soluble in water.
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS
Barium sulfate is much less soluble in water than either of sodium chloride and sodium chloride. When mixed, the solubility of the barium sulfate is exceeded. The barium sulfate then precipitates as fine solids, which remain suspended but scatter light to produce the milky look. Added: Na+ (sodium ion) and Cl- (chloride ion) don't react, Only Ba2+ and SO42- do so by forming precipitate: SO42- + Ba2+ --> (BaSO4)s
barium chloride plus sodium sulphate yields barium sulphate plus sodium chloride
The balanced chemical equation for Barium chloride plus Aluminium sulphate gives Barium sulphate Aluminium chloride is represented as .3BaCl2(aq) + Al2(SO4)3(aq) --> 3BaSO4(ppt) + 2AlCl3(aq).The ppt formed are white in color.
The ionic equation for barium chloride (BaCl2) plus copper sulfate (CuSO4) is Ba2+ + SO4^2- → BaSO4(s) and Cu2+ + 2Cl- → CuCl2. This suggests the formation of a white precipitate of barium sulfate and copper chloride in solution.