when barium chloride reacts with copper sulphate a double dispacement resction takes place,where:
BaCl2(aq) + CuSO4(aq) --> BaSO4(s) + CuCl2(aq)
The ionic equation is more descriptive:
Ba2+ + 2Cl- + Cu2+ + SO4^2- --> BaSO4(s) + Cu2+ + 2Cl-
The net ionic equation tells us that barium ions will always react with sulfate ions to make an insoluble product.
Ba2+ + SO4^2- --> BaSO4(s)
The molecular equation for the reaction between copper (II) sulfate and barium chloride is: CuSO4 + BaCl2 -> BaSO4 + CuCl2. In this reaction, the copper (II) ions switch places with the barium ions to form barium sulfate and copper (II) chloride.
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
Cu2+ + (SO4)2- + Ba2+ + 2Cl- = Cu2+ + 2Cl- + BaSO4 (s)
When calcium chloride is mixed with copper sulfate, a white precipitate of calcium sulfate forms due to the displacement reaction between calcium and copper ions. This reaction is a double displacement reaction in which calcium sulfate and copper chloride are formed.
When copper nitrate reacts with barium chloride, a white precipitate of barium nitrate is formed. Copper chloride remains in solution as ions. This reaction can be represented by the equation: Cu(NO3)2 + BaCl2 -> Ba(NO3)2 + CuCl2.
The molecular equation for the reaction between copper (II) sulfate and barium chloride is: CuSO4 + BaCl2 -> BaSO4 + CuCl2. In this reaction, the copper (II) ions switch places with the barium ions to form barium sulfate and copper (II) chloride.
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
The net ionic equation for the reaction between copper(II) nitrate (Cu(NO3)2) and barium chloride (BaCl2) is: Cu2+ (aq) + 2Cl- (aq) → CuCl2 (s). This shows the formation of insoluble copper(II) chloride precipitate.
The chemical equation for the reaction between barium chloride (BaCl2) and copper sulfate (CuSO4) is: BaCl2 + CuSO4 -> BaSO4 + CuCl2. This reaction forms barium sulfate (BaSO4) and copper (II) chloride (CuCl2) as the products.
Cu2+ + (SO4)2- + Ba2+ + 2Cl- = Cu2+ + 2Cl- + BaSO4 (s)
The complete ionic equation for the reaction between copper(II) sulfate and barium chloride is: Cu^2+(aq) + SO4^2-(aq) + 2Ba^2+(aq) + 2Cl^-(aq) → BaSO4(s) + CuCl2(aq)
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2
When barium sulfate reacts with copper sulfate, a double displacement reaction occurs. Barium sulfate and copper sulfate exchange ions to form barium sulfate and copper sulfate precipitates. The reaction results in the formation of a white solid of barium sulfate, which is insoluble in water.
BaCl2 + CuSO4 = BaSO4 = CuCl2
The word equation for copper sulfate and water is: copper sulfate + water → copper sulfate solution.
Barium salts, such as barium chloride or barium nitrate, are commonly used to produce a green flame when burned. The green color is a result of the specific wavelength of light emitted by the barium ions during the combustion process.
Barium sulfate is insoluble in water, while copper sulfate is soluble. This is due to differences in the solubility rules for these ions in water. Barium sulfate forms a highly insoluble precipitate, while copper sulfate dissociates into its ions in water.