+6 for each Cr
-2 for each O
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∙ 11y agoThe oxidation number of chromium (Cr) in dichromate ion (Cr2O7^2-) is +6. This is because oxygen (O) is typically assigned an oxidation number of -2, and the overall charge of the ion is -2, so the two chromium atoms must have a total oxidation number of +12 to balance the charge.
The oxidation number of oxygen in Cr2O7 is -2. Since there are seven oxygen atoms in the dichromate ion (Cr2O7), and the overall charge of the ion is -2, each oxygen atom is assigned an oxidation number of -2.
The oxidation number for Cr in Cr2O7^2- is +6. Each oxygen atom has an oxidation number of -2, so the sum of the oxidation numbers in the compound must equal the charge of -2 for the entire ion.
The oxidation number for Cr in Cr2O7^2- is +6.
The oxidation number of chromium (Cr) in Cr2O7^2- is +6. This can be determined by assigning oxygen an oxidation number of -2 and setting up an equation based on the overall charge of the ion.
The new oxidation number for Cr2O7^2- is +6, for H is +1, for SO3^2- is +4, for Cr3+ is +3, for SO4^2- is +6, and for H2O is 0.
The oxidation number of oxygen in Cr2O7 is -2. Since there are seven oxygen atoms in the dichromate ion (Cr2O7), and the overall charge of the ion is -2, each oxygen atom is assigned an oxidation number of -2.
The oxidation number for Cr in Cr2O7^2- is +6. Each oxygen atom has an oxidation number of -2, so the sum of the oxidation numbers in the compound must equal the charge of -2 for the entire ion.
The oxidation number for Cr in Cr2O7^2- is +6.
The oxidation number of chromium (Cr) in Cr2O7^2- is +6. This can be determined by assigning oxygen an oxidation number of -2 and setting up an equation based on the overall charge of the ion.
The new oxidation number for Cr2O7^2- is +6, for H is +1, for SO3^2- is +4, for Cr3+ is +3, for SO4^2- is +6, and for H2O is 0.
The oxidation number of chromium in Cr2O7 is +6. Each oxygen atom has an oxidation number of -2, and the overall charge of the Cr2O7 ion is -2, so the total oxidation number for the two chromium atoms must equal +12 to balance it out. Therefore, each chromium atom has an oxidation number of +6.
In K2Cr2O7, the oxidation number of oxygen is typically -2. Since there are two oxygen atoms in the dichromate ion (Cr2O7)^2-, the total oxidation number contribution from oxygen is -14. To balance this, the oxidation number of Cr is +6. Therefore, the oxidation number of O in this compound is -2.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
The oxidation number of Cr in Cr2O7^2- ion is +6. Each oxygen atom has a -2 charge, and the overall charge of the ion is 2-, so combining the charges gives -2*(-7) = -14. Since the overall charge is 2-, the oxidation number of Cr must be +6 to balance the charges.
The oxidation number of Cr in HCr2O7 is +6. This is because each oxygen atom has an oxidation number of -2, and there are four oxygen atoms in the dichromate ion (Cr2O7)^2-. The overall charge of the ion is -2, which means the two chromium atoms must have a total oxidation number of +12 to balance the charge, resulting in an individual oxidation number of +6 for each chromium atom.
The oxidation number of magnesium in magnesium dichromate (MgCr2O7) is +2. In dichromate ion (Cr2O7^2-), each oxygen atom has an oxidation number of -2. Since the overall charge of the dichromate ion is -2, each chromium atom must have an oxidation number of +6, and each magnesium atom must have an oxidation number of +2 to balance the charges.
In this reaction, chromium (Cr) is being reduced from a +6 oxidation state in Cr2O7 to a +3 oxidation state in 2Cr3+.