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What is the oxidation number for Cr2O7 -2?
The oxidation number of chromium (Cr) in Cr2O7^2- is +6. This can be determined by assigning oxygen an oxidation number of -2 and setting up an equation based on the overall charge of the ion.
What is oxidation number of CR2O7 2?
The oxidation number of chromium (Cr) in dichromate ion (Cr2O7^2-) is +6. This is because oxygen (O) is typically assigned an oxidation number of -2, and the overall charge of the ion is -2, so the two chromium atoms must have a total oxidation number of +12 to balance the charge.
Which answer is the oxidation number for Cr in Cr2Omc019-1jpg?
The oxidation number for Cr in Cr2O7^2- is +6.
What is the oxidation number for Cr in Cr2O7-2?
The oxidation number for Cr in Cr2O7^2- is +6. Each oxygen atom has an oxidation number of -2, so the sum of the oxidation numbers in the compound must equal the charge of -2 for the entire ion.
What is oxidation number of chromium in Cr2O7?
The oxidation number of chromium in Cr2O7 is +7. The oxidation number of oxygen is -2, so 7 O atoms times -2 = -14. In order to balance the -14 on the oxygen atom, each chromium atom must have an oxidation number of +7, because 2 Cr atoms times +7 equals +14.
What is the oxidation number for Cr2O7 -2?
The oxidation number of chromium (Cr) in Cr2O7^2- is +6. This can be determined by assigning oxygen an oxidation number of -2 and setting up an equation based on the overall charge of the ion.
What is oxidation number of CR2O7 2?
The oxidation number of chromium (Cr) in dichromate ion (Cr2O7^2-) is +6. This is because oxygen (O) is typically assigned an oxidation number of -2, and the overall charge of the ion is -2, so the two chromium atoms must have a total oxidation number of +12 to balance the charge.
Which answer is the oxidation number for Cr in Cr2Omc019-1jpg?
The oxidation number for Cr in Cr2O7^2- is +6.
What is the oxidation number for Cr in Cr2O7-2?
The oxidation number for Cr in Cr2O7^2- is +6. Each oxygen atom has an oxidation number of -2, so the sum of the oxidation numbers in the compound must equal the charge of -2 for the entire ion.
What is oxidation number of chromium in Cr2O7?
The oxidation number of chromium in Cr2O7 is +7. The oxidation number of oxygen is -2, so 7 O atoms times -2 = -14. In order to balance the -14 on the oxygen atom, each chromium atom must have an oxidation number of +7, because 2 Cr atoms times +7 equals +14.
What is the oxidation number for 0 in k2cr207?
In K2Cr2O7, the oxidation number of oxygen is typically -2. Since there are two oxygen atoms in the dichromate ion (Cr2O7)^2-, the total oxidation number contribution from oxygen is -14. To balance this, the oxidation number of Cr is +6. Therefore, the oxidation number of O in this compound is -2.
What is the oxidation number of Cr in Cr2O72 is?
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
What is the new oxidation number for cr2o7-2 plus 8h plus 3so3-2 2cr3 plus 3sov-2 plus 4h20?
oxidation number of S is +6.It oxidize into SO4 ^-2
What element is reduced in this reaction cr2o7 3hno2 5h-2cr3 3no3 4h2o?
In this reaction, chromium (Cr) is being reduced from a +6 oxidation state in Cr2O7 to a +3 oxidation state in 2Cr3+.
What is the oxidation number of H2O2?
The oxidation number for H is +1, and the oxidation number for O is -1.
What is oxidation number of N2O5?
In N2O5, the oxidation number of N (nitrogen) is +5 and the oxidation number of O (oxygen) is -2.
What are the oxidation numbers for each atom involved in the reaction 4ko2 and 2co2-2k2co3 and 3co2?
In KO2, O has an oxidation number of -1, K has an oxidation number of +1. In CO2, O has an oxidation number of -2, C has an oxidation number of +4. In K2CO3, O has an oxidation number of -2, C has an oxidation number of +4, and K has an oxidation number of +1. In the given reaction, the oxidation numbers for each atom remain the same as in their individual compounds.
