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The oxidation number of chromium in Cr2O7 is +7. The oxidation number of oxygen is -2, so 7 O atoms times -2 = -14. In order to balance the -14 on the oxygen atom, each chromium atom must have an oxidation number of +7, because 2 Cr atoms times +7 equals +14.

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11y ago
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10y ago

True however I believe the question did not place Chromium in any compund therefore technically its oxidation number would be O as it is in its natural state as Cr.

Chromium (symbol: Cr) can have several oxidation numbers, depending on the nature of the compound it is found in. Possible oxidation numbers for Chromium are:

  • 6
  • 5
  • 4
  • 3
  • 2
  • 1
  • -1
  • -2
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11y ago

+1 for each Cs, -2 for each O, +6 for each Cr

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11y ago

The oxidation number of chromium in the dichromate polyatomic ion, Cr2O72-, is +6.

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11y ago

+6 for each Cr and -2 for each O

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13y ago

+6

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Q: What is oxidation number of chromium in Cr2O7?
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What is the oxidation number of O of Cr2O7?

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