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Ar of N = 14g/mol

Ar of H = 1g/mol

Ar of S = 32.1g/mol

Ar of O = 16g/mol

Mr of (NH4)2SO4 = 2[14+4(1)]+32.1+4(16) = 132.1g/mol

There are two nitrogen atoms in one molecule of (NH4)2SO4

Therefore the mass of nitrogen = 2(14) = 28g/mol of (NH4)2SO4

Percentage of mass composition of nitrogen = (28/132.1) x 100% = 21.2%

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