major component of power loss in a transformer is secondary resistance.when transformer is operated under no load,no current flows through the secondary.so under no load conditions transformer has just very small megnetic losses.
This depends on construction; 5 watts per kVA is a good swag.
To calculate the no load current from transformer & core loss is also calculated.
The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)
It is always desirable to run any equipment or device at maximum efficiency for that matter, not only the power transformer. Power transformer maximum efficiency occurs when copper loss is equal to iron loss. (or no load loss equals to load loss). This does not necessariliy mean that maximum efficiency occurs at maximum or full load. Generally the maximum efficiency occurs at relatively less than full load of the transformer.
The copper losses, because they vary as the square of the secondary/primary currents.
Measuring No-LoadIn theory the no-load current of a transformer is zero. But in practice there is iron loss and core loss in the transformer, so there is power loss. Connect an ammeter in series with the stabilizer to measure the no-load current. Check your energy meter at no-load to see how much power is consumed. Ohms law: I(Amps) = E(voltage) divided by R(resistance). In the case of coils (transformer), the resistance of the coil would simply be the total impedance (Z). If I am remembering this correctly, you get, I=E/(R+Z)
the efficiency is maximum in a transformer when no load loss is equal to load loss.
Copper loss varies with the load.
To calculate the no load current from transformer & core loss is also calculated.
The maximum efficiency condition in distribution transformer is said to be occurred when iron loss = copper loss
The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)
It is always desirable to run any equipment or device at maximum efficiency for that matter, not only the power transformer. Power transformer maximum efficiency occurs when copper loss is equal to iron loss. (or no load loss equals to load loss). This does not necessariliy mean that maximum efficiency occurs at maximum or full load. Generally the maximum efficiency occurs at relatively less than full load of the transformer.
That type of transformer normally has about 99% efficiency so the full-load loss would be 1% or 6 kW.
The copper losses, because they vary as the square of the secondary/primary currents.
Yes because the transformer heating (power losses) depend on the load current and the load voltage. It can be assumed that the voltage stays more or less constant, therefore the iron loss is also constant. The copper loss depends on the square of the load current. So it is the VA of the load that determines the power loss and any heating.
Measuring No-LoadIn theory the no-load current of a transformer is zero. But in practice there is iron loss and core loss in the transformer, so there is power loss. Connect an ammeter in series with the stabilizer to measure the no-load current. Check your energy meter at no-load to see how much power is consumed. Ohms law: I(Amps) = E(voltage) divided by R(resistance). In the case of coils (transformer), the resistance of the coil would simply be the total impedance (Z). If I am remembering this correctly, you get, I=E/(R+Z)
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
eddy current loss in the transformer core is reduced by