1 mL solution contain 1 mg potassium permanganate.
Assuming that the questioner meant to write "permanganate" instead of "promangenate", the answer may be found as follows: The formula of potassium permanganate is KMnO4, showing four atoms of oxygen per formula unit. The formula unit mass of KMnO4 is 158.03; therefore, 17.7 g of potassium permanganate contains [4(17.7)/158.03](Avogadro's Number) or 2.70 X 1023 atoms of oxygen, to the justified number of significant digits.
3.62 percent by mass means that there are 3.62 g NaOCl per every 100 g of solution. So, to find grams in 1911.9 g solution, just multiply ...3.62 g NaOCl/100 g soln x 1911.9 g soln = 69.2 g NaOCl
Potassium levels in humans are measured in a unit known as milliEquivalents per Liter or (mEq/L).
58.08 (SCN-) + 39.10 (K+) = 97.18 gram/mol KSCN0.1 N = 0.1 M = 0.1 (mol/L) * 97.18 (g/mol) = 9.718 g KSCN per litre.
-- Take the number of percent. -- Multiply it by 10,000-- The answer is the number of parts per million. . 10 percent = 100,000 parts per million.
Ferrous chloride in presence of hydrochloric acid gives brown precipitates of Ferric chloride with potassium permanganate.
Assuming that the questioner meant to write "permanganate" instead of "promangenate", the answer may be found as follows: The formula of potassium permanganate is KMnO4, showing four atoms of oxygen per formula unit. The formula unit mass of KMnO4 is 158.03; therefore, 17.7 g of potassium permanganate contains [4(17.7)/158.03](Avogadro's Number) or 2.70 X 1023 atoms of oxygen, to the justified number of significant digits.
39.0983 ± 0.0001 u
Fumigation is usually done with formaldehyde gas using 40 ml of 40 per cent commercial formalin and 20 g of potassium permanganate for each 2á8 m3 of space inside the incubator or hatcher. Potassium permanganate may be placed in a glass or earthenware container and formalin poured over it. Fumigation should preferably be done-at the end of the working day and then the rooms closed.
3.62 percent by mass means that there are 3.62 g NaOCl per every 100 g of solution. So, to find grams in 1911.9 g solution, just multiply ...3.62 g NaOCl/100 g soln x 1911.9 g soln = 69.2 g NaOCl
In late 2008, bulk potassium was about $ 40 USD per pound.The price for the salt "potassium chloride" was only about 1% of that price, but sharply higher in 2009 (around $ 10 USD per pound in bulk).
Only possible to calculate approximately (without knowing densities of all solutions) when 'percent' means 'gram per 100 ml' or 'ml per 100 ml'Solve the following equations to find V1 and V2:7% * V1 (ml) + 45% * V2 (ml) = 15% * 800 (ml)V1 (ml) + V2 (ml) = 800 (ml) [Especially this 2nd equation in an approximation]Outcome: 632 and 168 ml respectively, but this is an approximation! (due to the ignoring of volume contraction: mixing will result in LESS ml's than 800 ml, so concentration will be more than 15%)
2K2MnO4 + Br2 ----> 2KMnO4 + 2KBr
Corn is in the moderate potassium chart per cup its 100to200 mg
KMnO4.
Per unit of weight, bananas have three times as much potassium.
Because the word "percent" derives from per + cent= per 100.Because the word "percent" derives from per + cent = per 100.Because the word "percent" derives from per + cent = per 100.Because the word "percent" derives from per + cent = per 100.