Only possible to calculate approximately (without knowing densities of all solutions) when 'percent' means 'gram per 100 ml' or 'ml per 100 ml'
Solve the following equations to find V1 and V2:
Outcome: 632 and 168 ml respectively, but this is an approximation! (due to the ignoring of volume contraction: mixing will result in LESS ml's than 800 ml, so concentration will be more than 15%)
The mass of NaCl is 14,61 g.
Divide grams (mass) by molar mass to find moles58.44 (g NaCl/L) / [22.99+35.45](g NaCl/mol NaCl)= 1.000 mol/L NaCl
Hno2+nacl
[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M
Take 1000 ml volumetric flask weigh 2.542 g of Nacl
The answer is 0,9 g pure, dried NaCl.
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
The mass of NaCl is 14,61 g.
Dissolve 3 g NaCl in 100 mL water.
Reactions are: 2Na + Cl2 = 2NaCl NaOH + HCl = NaCl + H2O
The answer is 26,3 g.
Moles of NaCl=6*3=18mol Mass needed=[35.5+23]*18=1053g
Sodium chloride is a solute when is dissolved in water (the solvent).
Dissolve 0,9 g sodium chloride in 100 mL distilled water.
Dissolve 5 g salt in 100 mL water at 20 0C.
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