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"R2O is oxides ofalkaline metals Li2O, Na2O, K2O" from: elearning.rmutl.ac.th/main/mod/resource/view.php?id=9188
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Why is R?
Element R takes a slightly positive charge, while O takes and negative charge. The charge on O is twice R therefore you need two R's to balance R2O. Because the R's are on either side of the O and the attraction is from to positive, the charges cancel each other out due to symmetry, one goes left 1 unit, the other goes right 1 unit, as they have an equal charge.
Why R-O-R is polar?
Element R takes a slightly positive charge, while O takes and negative charge. The charge on O is twice R therefore you need two R's to balance R2O. Because the R's are on either side of the O and the attraction is from to positive, the charges cancel each other out due to symmetry, one goes left 1 unit, the other goes right 1 unit, as they have an equal charge.
What would happen if a piece of rubidium were dropped in water?
As rubidium is a group one element, it has only the 5s1 electron in its outer energy level which makes it very reactive. So, if we were to drop some rubidium in water it would react rapidly to produce smoke and small sparks. There are lots of YouTube videos of this reaction so take a look.
What ester is formed when methanol reacts with acetic acid?
The reaction of acetic acid and methanol affords water and an ester, namely methyl methanoate. The mechanism of this reaction can involves two pathways. In one, the hydroxyl hydride is displaced by a strong base, leaving a methanoate anion, which nucleophilically attacks the methyl group of the alcohol. Also, the carbonyl double bond of the acid can form a bond with the methyl group. The hydroxyl group of what used to be methanol leaves. Immediately following, the O-H bond of the acetic acid collapses to form a carbonyl, a proton is abstracted, which reacts with the hydroxide left from the loss of hydrogen from the water to form methyl methanoate and water. See esterfication and Fischer esterfication
