Acetic acid cannot further oxidation to any ketone or whatever, but at some condition it may burn to produce Carbon dioxide and water:
CH3COOH + 2 O2 ----> 2 CO2 + 2 H2O
W. Edward Lendsell and Peter N. Preston of Herriot-Watt University, Edinburgh, have developed (Tetrahedron Lett.2005, 46, 8695. doi("10.1016/j.tetlet.2005.10.038") DOI: 10.1016/j.tetlet.2005.10.038) a new family of Pd catalysts, exemplified by the complex 2. These catalysts efficiently (1 mol %) mediate homologation of benzylic halides such as 1 to the corresponding methyl esters at low temperature (35°C) and modest CO overpressure (3.45 bar).
Sukbok Chang of KAIST, Daejon, Korea has uncovered (J. Am. Chem. Soc. 2005, 127, 16046. doi("10.1021/ja056399e") DOI: 10.1021/ja056399e) a truly remarkable reaction, the hydrative conversion of a terminal alkyne such as 4 to the N-sulfonyl amide 5. The free amide 6 can be released by dissolving metal reduction. It is likely that 5 could be N-alkylated efficiently, including under Mitsunobu conditions. The sulfonyl amide 5may also behave like a Weinreb amide, allowing efficient coupling with organometallic nucleophiles to form the corresponding ketones.
Another remarkable set of transformations has been reported (Org. Lett. 2005, 7, 5237. doi("10.1021/ol052100l") DOI: 10.1021/ol052100l) by Sonia I. Maffioli of Vicuron Pharmaceuticals, Gerenzano, Italy. Exposure of a nitrile 7 to a catalytic amount (as little as 0.5 mol %) of PdCl2 (Pd(OAc)2 served equally well) in the presence of acetamide led to the primary amide 8. Conversely, the same catalyst in the presence of acetonitrile converts the primary amide 8 to the nitrile 7. These reactions run at or slightly above ambient temperature.
There is no reaction. Acetic acid is a kind of carboxylic acid.
The chemical equation is:
CH3COOH + KOH = CH3COOK + H2O
When KOH reacts with HCl, these products are formed. This is a neutralization reaction. KOH is a base while HCl is an acid.
Neutralization is the reaction between an acid and a base and formation of a salt and water.ExampleHCl + NaOH ------> NaCl + H2OH2SO4 + 2NaOH ----> Na2SO4 + 2H2OHNO3 + KOH -----> KNO3 + H2OCH3COOH + NaOH ----> CH3COONa + H2O
HCl + KOH --> KCl + H2O Hydrochloric Acid + Potassium Hydroxide --> Potassium Chloride + Water.
React aniline with HCl/NaNO2 (diazotisation) followed by reaction with KOH to give phenol. Nitration of phenol with fuming nitric acid gives picric acid (or trinitrophenol).
You would add either ammonium nitrate or nitric acid.
Acetic acid is an organic acid an d it reacts with potassium hydroxide to form salt and water Its neuatralisation reaction CH3CooH + KOH -------> CH3COOK + H2O
0.13 is the concentration of the acetic acid solution.
You can add KOH and HCl.It gives out KCl.
A salt is the product of the reaction between a base and an acid; potassium chloride may be obtained from HCl and KOH: HCl + KOH = KCl + H2O
Stearic acid reacts with potassium hydroxide to form water and potassium stearate. The reaction equation is C18H36O2 + KOH = C18H35O2K + H2O.
The stated reaction is an example of a neutralization reaction between an acid and a base forming a product salt and water. The equation of the reaction is HNO3 + KOH -> KNO3 + H2O.
There will be no reaction.
There is no reaction
CH3COOH + KOH = CH3COOK + H2O
HC2H3O2(aq) + KOH(aq) → KC2H3O2(aq) + H2O(l)...... I don't know about Net Ionic, but i think this is correct
Potassium sulphate and water: H2SO4 + 2 KOH----------K2SO4 + 2H2O
KOH + HCl ---> KCl + H2O