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What is relation between IC AND IB?

Updated: 12/20/2022
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Q: What is relation between IC AND IB?
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How to calculate the current gain in darlington pair?

start at Ic'= Ic1+Ic2 Ib'=Ib1 Ic1=B1*Ib' Ie1=Ib2=Ib'(B1+1)=Ib'B1 + Ib' Ic' = Ib'*B1 + Ic2 Ic2= B2(Ib'B1+Ib') Ic' = Ib'B1 + Ib'B1B2 + Ib'B2 divide by Ib' Ic'/Ib'= current gain =B'=B1+B2+B1B2 note: calculations without resistance


The current amplification factor adc is given by?

IC/IB where IC is Collector Current and IB is Base Current


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Emitter current can be summed up by the formula: IE = IC+ IB Where IE = Emitter Current, IC = Collector Current, and IB = Base Current So simply take IE - IC and you'll get an IB of about 100uA. (5mA-4mA = .1mA or 100uA) Also, remember that IB controls IC and IE, not the other way around. You can also determine IB if Beta is known by the formula: IC = IB * Beta Which can be manipulated to equal IB = IC/Beta Hope this was helpful.


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beta dc= ic/ib!!


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Consider that current flow "enters" at the emitter and "exits" at the collector and base. Now, IE = IB + IC. Alternately, current "enters" at the collector and the base, and "exits" at the emitter. Now, IE = IB + IC


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