All resistances will emit heat energy when a current flows. The heat production rate (or power) can be found by any of these formulas:
Power = Current * Voltage
Power = Current2 * Resistance
Power = Voltage2 / Resistance.
Power is given in Watts when Current is in Amps, Voltage in Volts, and Resistance in Ohms.
Power is inversely proportional to resistance. Ohm's law: Current is voltage divided by resistance Power law: Power is voltage times current, therefore power is voltage squared divided by resistance.
when source resistance and load resistance are equal maximum power is transfered
First, this statement stands as long as voltage is constant. If you held the current constant then power would increase as resistance increases.V=IR. For a fixed voltage if you increase the resistance (R) then the current (I) will decrease - following the formula.Power = VI so as the resistance increases the value of VI (power) decreases as V is constant and I gets smaller.Therefore the power is decreasing as the resistance increases (when voltage is held constant).Hope this helps.
Short answer: yes. Most modern multimeters will not be damaged by external power when measuring resistance. But they will give erroneous readings. It is best to remove the power and disconnect the measured resistance from the larger circuit. A multimeter determines resistance by applying a small voltage, and measuring the resulting current. If the resistor has an external voltage source, then it will interfere with the measurement. Furthermore, if the resistance is connected to a larger circuit, then the resistance of this larger circuit will also be involved.
inductance
power=i square*resistance or power=v suare/resistance
Since power = voltage2/resistance, reducing the resistance will increase the power of the circuit. Incidentally, power is not 'consumed'; it's energy that's consumed.
Power=current squared times resistance
Power is inversely proportional to resistance. Ohm's law: Current is voltage divided by resistance Power law: Power is voltage times current, therefore power is voltage squared divided by resistance.
yes, batteries have high internal resistance. The higher the resistance the lower power you get out of the batter. Therefore if you no power you have very high resistance.
if the resistance is decreased and the current stays the same, then the power decreases.
Power is voltage squared, divided by resistance (P = V2/R) so, for a given voltage, the lower the resistance, the greater the power!
Power consumed by a resistance is I2R
A cable power or otherwise has no final or beginning resistance unless power is applied. therefore no unswer to the question
Power = 1 A and resistance = 1100 Ohms.
A coil of wire acts as an inductor; it will have a very small resistance, and a relatively large inductance. Power factor is effectively the resistance divided by the impedance (made up of resistance and inductance), so the larger the inductance relative to the resistance, the lower the power factor will be.
Knowing P=VI and R=V/I we derive that P=VxV/R i.e. resistance is inversely proportional to power. Resistance for a higher power is lower.