when source resistance and load resistance are equal maximum power is transfered
internal resistance is always infinite in ideal current source .the internal resistance is in shunt with current source
in case of ideal voltage source we consider the internal resistance to be zero.but in practical,every battery has some internal resistance then if you connect a load resistance across the terminals of that source,the net potential difference's across the voltage source will be a function of external resistance connects it won't give constant voltage across it's terminals.
use kvl or kcl
Take the internal series resistance of the voltage source and make it the internal parallel resistance of the current source. Then compute using Ohm's law the current of the current source to be equal to the maximum current the original voltage source could supply a short circuit load. Note: the two sources are equivalent.
yes
Current equals Voltage divided by Resistance. 9/2=4.5 amps.
It is not recommended because one or other current source will be damaged by excessive voltage.
THE brightness would decrease as solenoid would have some resistance.
A:is equal to the source
it is a type of resistance which inbuilt in voltage source
Current source means current generator for a circuit. An ideal current source gives all current to the circuit, but practically a current source does n't give all current to the circuit, instead, a source resistor is connected in parallel to the current source to indicate the current drop.
internal resistance is always infinite in ideal current source .the internal resistance is in shunt with current source
resistance does not produce currents . you need source (like voltage source , current source ,or , discharging capacitor) to generate current .
Voltage source: is any source that voltage and amperage come from. Resistor: is any part of a circuit that consumes that energy!
It isn't. See the answer to your question about a current source.
in case of ideal voltage source we consider the internal resistance to be zero.but in practical,every battery has some internal resistance then if you connect a load resistance across the terminals of that source,the net potential difference's across the voltage source will be a function of external resistance connects it won't give constant voltage across it's terminals.
You can't convert kV (kilovolts) to current (amps) unless you know the resistance (ohms) of the load which is taking current from that voltage source. Once you know the resistance then you can use Ohm's Law to get the amperage: I = V / R In words, Ohm's law is: Current (amps) equals voltage divided by resistance (ohms)