Return value 1 from a function is a true value and generally means success.
Return value 1 from the outermost function, i.e. to the shell, however, is a failure indication, and the value is dependent on the design of the code.
In other words: context-dependent, always consult the documentation.
int myfun (void) { return 4*2*1; }
A method that return a value should have a return statement. The method signature should indicate the type of return value. While in the case of a method that does not return a value should not have a return statement and in the signature, the return type is void. When using a method that doesn't return a value, a programmer can not get a value from that function, but instead, it can only change variable values and run other methods.
It is a syntax error, because a value returning method must return a value, and not writing a return statement with a value is tantamount to returning without a value.
The return statement is used in functions to return control to the caller. If the function is declared non-void, the return statement also allows the programmer to return a value to the caller.
It means end the function. Functions automatically end when execution reaches the end of the function, but you can return from a function at any point within the function with a return statement. If the function returns a value to its caller, you must provide a reachable return statement along with the value you wish to return.
Yes: unsigned char CircLeft (unsigned char value) { if (value&0x80) return (value<<1) + 1; else return (value<<1); } unsigned char CircRight (unsigned char value) { if (value&0x01) return (value>>1) + 0x80; else return (value>>1); }
int myfun (void) { return 4*2*1; }
Returning a value of 1 (or any value besides zero) from main indicates an error.
A method that return a value should have a return statement. The method signature should indicate the type of return value. While in the case of a method that does not return a value should not have a return statement and in the signature, the return type is void. When using a method that doesn't return a value, a programmer can not get a value from that function, but instead, it can only change variable values and run other methods.
C does not prove a built-in function to determine if a number is prime or not, thus we must write one. The implementation is reasonably trivial: bool is_prime (unsigned int value) { if (value<2) return false; if (!(value%2)) return value==2; unsigned int max_factor, factor; max_factor = sqrt (value) + 1; for (factor=3; factor<max_factor; factor+=2) if (!(value%factor)) return false; return true; } That is; we return false when value is less than 2 (because 2 is the first prime). If the value is even, we return true if the value is 2 (because 2 is the only even prime). For all other values greater than 2, we divide the value by increasing odd factors (3, 5, 7, 9, etc) up to the square root of the value. If the value is evenly divisible by any of these (potential) factors, the number cannot be prime so we return false. If none of the potential factors evenly divides into the value, the value is prime so we return true. Given this function, we can now create another function that will determine the next prime after any given value (the given value need not be prime). unsigned int next_prime (unsigned int value) { while (!is_prime (++value)); return value; } Here we increment the value until the is_prime() function returns true, at which point we return the value, which is now prime. Now we can print all the prime numbers from 1 to 100: int main (void) { int n; n=1; while ((num=next_prime (num))<=100) { printf ("%d\n", num); } return 0; }
It is a syntax error, because a value returning method must return a value, and not writing a return statement with a value is tantamount to returning without a value.
The return statement is used in functions to return control to the caller. If the function is declared non-void, the return statement also allows the programmer to return a value to the caller.
Below is a simple example of how you could return a value in a PHP function. <?php function returnme($value) { return $value; } echo returnme('hello'); // outputs: hello ?>
It means end the function. Functions automatically end when execution reaches the end of the function, but you can return from a function at any point within the function with a return statement. If the function returns a value to its caller, you must provide a reachable return statement along with the value you wish to return.
you++ will return the current value of you and increment it. ++you will increment it and then return the new value of you. So, for example: int you = 0; cout << you++; // this will print 0 cout << you; // this will print 1 int you = 0; cout << ++you; // this will print 1 cout << you; // this will also print 1
No, it is a function. But printf does return a value: the number of characters it has written.
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