0
// Swap
// Demonstrates passing references to alter argument variables
#include
<iostream>
using
namespace std;
void
badSwap(int x, int y);
void
goodSwap(int& x, int& y);
int
main()
{
int myScore = 150;
int yourScore = 1000;
cout <<
"Original values\n";
cout <<
"myScore: " << myScore << "\n";
cout <<
"yourScore: " << yourScore << "\n\n";
cout <<
"Calling badSwap()\n";
badSwap(myScore, yourScore);
cout <<
"myScore: " << myScore << "\n";
cout <<
"yourScore: " << yourScore << "\n\n";
cout <<
"Calling goodSwap()\n";
goodSwap(myScore, yourScore);
cout <<
"myScore: " << myScore << "\n";
cout <<
"yourScore: " << yourScore << "\n";
return 0;
}
void
badSwap(int x, int y)
{
int temp = x;
x = y;
y = temp;
}
void
goodSwap(int& x, int& y)
{
int temp = x;
x = y;
y = temp;
}
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
Even number progamm in c language?
swap(&grades[num],&grades[num+1]); what it make in a program?
How do we write c program without using swap to interchange values by accessing another variable?
int a,b; a=a+b; b=a-b; a=a-b; that's it simple
Program in c using pointers to interchange 2 values without using third variable?
swap (int *pa, int *pb) { *pa ^= *pb; *pa ^= *pa; *pa ^= *pb; }
C program was introduced in the year?
c program was introduced in the year 1972 by Dennis RitchieNo, it was the C language, not the C program.
How would you write a program to swap the values of character variable using call by address?
void swap (int* a, int* b) { if (!a !b) return; // can't swap a pointer to null *a^=*b^=*a^=*b; }
How do you write a program in C plus plus plus plus How do you write a program in C to swap two variables without using the third oneo swap two variables without using the third one?
To swap two variables without using a third variable, use exclusive or manipulation... a ^= b; b ^= a; a ^= b;
How do you swap two numbers in a C program?
Ellipses (...) used to emulate indentation... swap(int *a, int *b) { ... int temp; ... temp = *a; ... *a = *b; ... *b = temp; }
Even number progamm in c language?
swap(&grades[num],&grades[num+1]); what it make in a program?
A program to swap values using pass by value?
#include<conio.h> main() { int a,b; scanf("%d%d",&a,&b); printf("Before swapping A= %d B=%d",a,b); swap(a,b); getch(); } void swap(int a,int b) { int c; c=a; a=b; b=c; printf("After swapping A= %d B=%d",a,b); }
How do you write a program in C to swap two variables without using the third one using XOR?
a=a^b; b=a^b; a=a^b;
How do you write a program in c to swap two values by using functions?
#include using namespace std; void swap(int &a, int &b); int main() { int x=5,y=3; cout
C program to swapping two numbers using call by value method?
You have to pass the address of the variables.void swap (int *pa, int *pb){...}
How do we write c program without using swap to interchange values by accessing another variable?
int a,b; a=a+b; b=a-b; a=a-b; that's it simple
Write a program to swap two numbers using function?
swap (int *a, int *b) { *a ^= *b; *b ^= *a; *a ^= *b; }
How develop c program that swap two number with out using temporary variable?
void main() { int a=2,b=5; b=a+b; a=b-a; b=b-a; getch(); }
What is the amount of data and program instructions that can swap at a given time?
a page
How do you write a program in C to swap two variables using the third variable?
Consider the following declarations:int x = 0;int y = 1;In order to swap the values, we need to use a temporary variable:int t = x;x = y;y = t;However, it is possible to swap the values without using a third variable:x ^= y ^= x ^= y;
