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0.370/323=p/273

p=0.313atm

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12y ago
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3d ago

To find the pressure at standard temperature (0°C or 273 K), we can use the combined gas law. P1/T1 = P2/T2. Given that P1 = 0.370 ATM, T1 = 50°C + 273 = 323 K, and T2 = 273 K, we can solve for P2. Substituting the values gives P2 = (0.370 ATM * 273 K) / 323 K ≈ 0.312 ATM.

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Q: What is the A gas has a pressure of 0.370 ATM at 50.0 C What is the pressure at standard temperature?
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