0.370/323=p/273
p=0.313atm
To find the pressure at standard temperature (0°C or 273 K), we can use the combined gas law. P1/T1 = P2/T2. Given that P1 = 0.370 ATM, T1 = 50°C + 273 = 323 K, and T2 = 273 K, we can solve for P2. Substituting the values gives P2 = (0.370 ATM * 273 K) / 323 K ≈ 0.312 ATM.
The pressure is 5,33 at.
It is 500 deg F.
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. So, in this case, the number of moles in 500 L of He gas at STP would be 500/22.4 = 22.32 moles.
Water boils at a lower temperature on a hill due to decreased atmospheric pressure at higher altitudes. For every 500 feet increase in elevation, the boiling point of water decreases by about 1 degree Fahrenheit.
A Tums tablet typically dissolves in vinegar within a few minutes due to the acid present in the vinegar reacting with the carbonate in the tablet. The specific time can vary depending on the temperature and concentration of the vinegar.
At standard temperature and pressure, water has a density of 1 gram per cubic centimeter, so 500 grams would be 500 cc (or 500 ml).
The pressure is 5,33 at.
500 mmHg or 500 torr is a gas pressure approximately 66% of the standard sea level air pressure of 760 torr ... it is the air pressure one would find at an altitude of approximately 3km or 10000 feet ... at sea level, 500 torr would be considered a partial vacuum of 0.66 atm.
That depends on what temperature it started at. Whatever scale of temperature you are using, water will be steam at 500 degrees.
500
Need more info as to which sending unit, oil pressure, coolant temperature or fuel level.
V = k*T/P Apart from the fact that a change in temperature from 20C to 80C cannot be described as a reduction, V2 = V1 * T2P1/T1P2 = 500*(273.15+80)*420/[(273.15+20)*650] = 500*353.15*420/(293.15*650) = 289.2 mL
where is low pressure valve on a 2005 ford 500? i am trying to add freon
The way you wrote it is the standard form.
According to Boyle's Law, the volume of a gas is inversely proportional to its pressure when temperature is constant. So, if the pressure increases from 740 Torr to 780 Torr, the volume will decrease accordingly. Using the formula P1V1 = P2V2, where P1 = 740 Torr, V1 = 500 ml, and P2 = 780 Torr, you can solve for V2 to find the final volume.
There are no 500 Series. lol
500,000,000,000