The volume of one mole of a gas at STP is 22.4 liters.
As oxygen is a diatomic gas it would take 6000 moles. As oxygen gas is 32 g/mole this would be 192000 grams or 192kg. At STP this would be a volume of (1)V =6000R(273) P=1atm R=8.314 v=13,618,332m3
Two samples of gas at STP containing the same total number of molecules would have equal volumes, as Avogadro's Principle states that equal volumes of gases contain equal numbers of molecules at the same temperature and pressure. Thus, 1 mole of any gas at STP will have the same number of molecules as 1 mole of any other gas at STP.
Argon is a gas at STP. It becomes a liquid below -186oC and solid below -190oC at StP
At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 5 liters of NO2 at STP will represent 0.22 moles (5/22.4), and this is the case for any other ideal gas. So, the answer is that 5 liter of ANY ideal gas will have the same number of molecules as 5 liters of NO2.
The gas sample that has the greatest number of molecules is the one with the largest amount of substance, which is measured in moles. At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. Therefore, the gas sample with the largest volume at STP will have the greatest number of molecules.
Assuming it acts as an ideal gas then you use the equation PV=nRT where P=pressure (101.325 kPa at STP) V = volume 444 L (given) n = number of mols R = gas constant, 8.314472 L kPa K-1mol-1 T = temperature 273.15 K at STP I got 19.81 mols.
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As oxygen is a diatomic gas it would take 6000 moles. As oxygen gas is 32 g/mole this would be 192000 grams or 192kg. At STP this would be a volume of (1)V =6000R(273) P=1atm R=8.314 v=13,618,332m3
Yes, the volume of a gas at Standard Temperature and Pressure (STP) can be calculated from the number of molecules using the ideal gas law. At STP (0°C and 1 atm), one mole of an ideal gas occupies 22.4 liters. Since Avogadro's number (approximately (6.022 \times 10^{23}) molecules) defines one mole, you can convert the number of molecules to moles and then multiply by 22.4 liters to find the volume at STP.
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. Therefore, a cylinder with a larger volume will contain more gas particles. Consequently, a cylinder with the greatest volume at STP will contain the highest number of gas particles, as the number of moles (and thus particles) increases with volume.
Two samples of gas at STP containing the same total number of molecules would have equal volumes, as Avogadro's Principle states that equal volumes of gases contain equal numbers of molecules at the same temperature and pressure. Thus, 1 mole of any gas at STP will have the same number of molecules as 1 mole of any other gas at STP.
Argon is a gas at STP. It becomes a liquid below -186oC and solid below -190oC at StP
1 mole of gas at STP occupies 22.4 liters.
At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 5 liters of NO2 at STP will represent 0.22 moles (5/22.4), and this is the case for any other ideal gas. So, the answer is that 5 liter of ANY ideal gas will have the same number of molecules as 5 liters of NO2.
The gas sample that has the greatest number of molecules is the one with the largest amount of substance, which is measured in moles. At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. Therefore, the gas sample with the largest volume at STP will have the greatest number of molecules.
1 mole of gas = 22.7 litre ( at STP) 22.7 Litre of gas = 1 mole 1 litre of gas = 2.27 litre of gas = mole www.examville.com