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What is the Amperes difference between a 2 light bulb series circuit and 2 light bulb parallel circuit?
Wiki User
∙ 14y ago
if the bulbs are identical, we can assume that both of them have the same resistance R.
in series :
the flowing current is I1, the voltage at the ends of the 1st Bulb is V1 and the voltage at the ends of the 2nd bulb is V2. V1 = V2 = V since they have the same resistance and V is the voltage applied on the ends of the whole circuit. the Total circuit resistance is 2*R.
thus : I1 = V / 2*R =>
V = 2 * I1 * R (1)
in Parallel mode :
the current flowing in the first bulb is i1 and the current flowing in the second bulb is i2.
i1 = i2 since R1 = R2.
I2 = i1 + i2
i1 = V / R and i2 = V / R =>
I2 = (V /R ) + (V / R) = 2*V / R =>
V = I2 * R / 2 (2)
(1) and (2) =>
2 * I1 * R = I2 * R /2 =>
I1 = I2 * R / (R * 2) =>
I1 = I2 / 2
above, is the mathematical solution of the problem, but the result is directly predictable since both bulbs are identical.
in summary the current that flows in the circuit when wired in series is half of the current when wired in parallel. also note, that the voltage in series on the ends of each bulb is half of the voltage when wired in parallel.
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoI presume that's 2 amps through EACH lamp. The answer is 4 amps.
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