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CT ratio is the ratio of primary (input) current to secondary (output) current. A CT with a listed ratio of 4000:1 would provide 1A of output current, when the primary current was 4000A.
Normally current transformers are used for two things . For measuring and protection. Whenever the CT is a protection CT it will be connected with the protection relays and there will be setting in the relays based on our requirement. when the current pass through the relays are more than the setting range then relay will send the tripping signal to the breaker available in the system to isolate the fault section. Finally the CT is not protecting the system. it will transfer the high primary current from the system to relay as small secondary current.
CL of a CT is its accuracy class.. it is an approximate measure of the CT's accuracy. e.g. The ratio (primary to secondary current) error of a Class 1 (CL:1.0) CT is 1% at rated current
A CT, or current transformer, has a specified current ratio. The 5 in your question is the current supplied to the metering instrument at full scale. CT's current ratio is always full scale to 5, for instance - 200:5, 3000:5, etc.So, if a CT has a ratio of, say, 1000:5, this means when the conductor being measured is supplying 1000 amperes to the load, the CT will output 5 amperes to the instrumentation. The relationship is linear, so if the current is 500 amperes, the output will be 2.5 amperes, at 200 amperes the output will be 1 ampere, etc.This is done so the instrument can be designed always the same, with a 5 ampere input, no matter what size current is to be measured. Otherwise you would have to order (and manufacture) many different models of meter, one for each current range.The metering must be set, or programmed, with the CT multiplier, so it knows how much current is really flowing when it sees 5 amperes on the input.Similarly, we use PT's or potential transformers to reduce higher system voltages to a range that the instrument can also handle.
Current transformers produce a ratio of primary current in the secondary. If the secondary of a CT is open circuited, and primary current is flowing, the CT will try to push that same ratio of current through the secondary open circuit. This causes secondary voltage to climb until it the secondary open circuit flashes over. This can often damage the CT.
CT ratio is the ratio of primary (input) current to secondary (output) current. A CT with a listed ratio of 4000:1 would provide 1A of output current, when the primary current was 4000A.
The CT standard output is 5 amps at the rated input amps. The CT will have a marking like 400:5, 100:5, or similar, where the bigger number is the input current that will cause 5 amps to flow in the CT secondary. Divide the span by 5 to get the multiplier. For instance: CT - 400:5 400 / 5 = 80 So, if you measure, say, 3 amps from the CT, the primary current is: 3 * 80 = 240 A
if you want to measure a wide range of current, example 1mA to 200A (if the device is intended for the metering and protection), normally CT and rocoil is used together, it is difficult to make rocoil sensitive in range of 1mA, but you can do the task with the CT, but the same CT gets saturated above 5A, in that case rocoil start measuring, since rocoil is air core it wont saturate.
Michael Pavia is the current mayor of Stamford, CT.
SCM CT is a normal CT which is connected in two phase of the turbines & its terminals are connected to the AVR. Depending on the load on the turbine the current increases & accordingly it gives the input to the AVR so as to develop the required field to generate the same load without any dip in the voltage.
ct is currrent transformer are use is protection instromentAnswerA current transformer is an instrument transformer. It allows the current flowing through high-voltage (h.v.) circuits to be monitored safely by (1) reducing the size of that current to a safe level, and (2) electrically isolating its secondary winding from the high-voltage system.A CT provides a safe means of (1) measuring the h.v. circuit's current, as well as (2) providing an input to the high-voltage system's protection relays.
CT (Current Transformer ) is essential whether is electronic relay or electromagnetic relay. A relay requires the CT to sense the line current.
Normally current transformers are used for two things . For measuring and protection. Whenever the CT is a protection CT it will be connected with the protection relays and there will be setting in the relays based on our requirement. when the current pass through the relays are more than the setting range then relay will send the tripping signal to the breaker available in the system to isolate the fault section. Finally the CT is not protecting the system. it will transfer the high primary current from the system to relay as small secondary current.
CL of a CT is its accuracy class.. it is an approximate measure of the CT's accuracy. e.g. The ratio (primary to secondary current) error of a Class 1 (CL:1.0) CT is 1% at rated current
CL of a CT is its accuracy class.. it is an approximate measure of the CT's accuracy. e.g. The ratio (primary to secondary current) error of a Class 1 (CL:1.0) CT is 1% at rated current
CT (current transformer) Burden is the maximum load that the CT secondary can drive (e.g. meters or protection relays) Why do you care about burden when ordering current transformers? The burden is the termination impedance of the measuring instrument. The measuring instrument can be an analog or digital energy meter, a data logger or a recorder. All instruments that use a current transformer to measure line current must terminate the CT with a resistance (impedance in same case which means there is some inductance involved). A CT supplier should be given the burden when ordering. Technically, the total burden for a CT is the internal winding resistance, the connecting lead resistance and the measuring instrument input resistance. Some Ct's are installed a long distance from the measuring instrument and the connecting leads can have a resistance as much as 0.002 ohms per foot (both ways because the current makes a complete round trip). This resistance will cause an error if not taken into account.
A CT, or current transformer, has a specified current ratio. The 5 in your question is the current supplied to the metering instrument at full scale. CT's current ratio is always full scale to 5, for instance - 200:5, 3000:5, etc.So, if a CT has a ratio of, say, 1000:5, this means when the conductor being measured is supplying 1000 amperes to the load, the CT will output 5 amperes to the instrumentation. The relationship is linear, so if the current is 500 amperes, the output will be 2.5 amperes, at 200 amperes the output will be 1 ampere, etc.This is done so the instrument can be designed always the same, with a 5 ampere input, no matter what size current is to be measured. Otherwise you would have to order (and manufacture) many different models of meter, one for each current range.The metering must be set, or programmed, with the CT multiplier, so it knows how much current is really flowing when it sees 5 amperes on the input.Similarly, we use PT's or potential transformers to reduce higher system voltages to a range that the instrument can also handle.