The CT standard output is 5 amps at the rated input amps. The CT will have a marking like 400:5, 100:5, or similar, where the bigger number is the input current that will cause 5 amps to flow in the CT secondary. Divide the span by 5 to get the multiplier. For instance: CT - 400:5 400 / 5 = 80 So, if you measure, say, 3 amps from the CT, the primary current is: 3 * 80 = 240 A
K=(voltmeter range*ammeter range*power factor)/wattmeter range
A 5P20 CT has a guaranteed error of less than 5% at 20 times it's rated current (in this case 5A, so at 100A), when it's secondary burden is at it's nominal VA rating. The acceptable ratio error has to allow the CT to perform within these bounds to be declared a 5P20 CT.
CL of a CT is its accuracy class.. it is an approximate measure of the CT's accuracy. e.g. The ratio (primary to secondary current) error of a Class 1 (CL:1.0) CT is 1% at rated current
Look for the ct (current transformer). You will find a ratio rating (for example, 200:5.) This means divide 200 by 5. The result is 40. Any difference in reading from a certain time should be multiplied by 40 to get actual energy consumption. This is the basic information, but in practice it should be calibrated by a government-certified body (the department of energy, for example) to perfectly match the kwhr-meter revolution.
'http://wiki.answers.com/Q/If_breaker_CT_ratio_8001_when_current_of_any_phase_crossed_800_ampere_what_would_happen'
multiplying factor = Line CT Ratio / Meter CT Ratio Usually it is mentioned on Meter that MF = 1 if CT Ratio is 200/5 or MF = 2 if CT Ratio is 400/5. There can be an additional multiplication factor that would be mentioned on the meter.
K=(voltmeter range*ammeter range*power factor)/wattmeter range
The question is incomplete, because there are no mention about CT & PT ratios. 600VA 5 can not be CT ratio.
mf is ratio of CT ration of meter box to CT ration written on meter. ex: CT meter box: 30/5, Meter ct ration 1/1. MF : (30/5)/(1/1)= 6
CT/5 /number of turns=multiplier
ct ratio test is the current between the primary to secondary
wattmeter is constructed such that it read only power on a single scale. Only single scale will avilable to read the measured power. In order to take the acuurate reading just we measure the reading and we will multiple along with factor called multificaion factor. That's depends on on which voltage knob we connected and also the current. Multification factor can be dtermind by: Multification factor =(voltage range*current range*pf)/Max scale deflection...
CT ratio is the ratio of primary (input) current to secondary (output) current. A CT with a listed ratio of 4000:1 would provide 1A of output current, when the primary current was 4000A.
The taper ratio of a wing is the ratio between the tipchord and the rootchord: ct/cr
If, Ct value = 50 meter unit = 30 so, 50 x 30 = 1500 kwh
Multiplication factor can be derived from Meter CT, Meter PT, Connected CT and Connected PT values.
How do you calculate mf with this following ct ratio 1. 75/5A, VA 5, Class 5.0, 660v. 2. 250/5A, VA 10, Class 1.0, 660V 3. 3200/5A, VA15, Class 1, 660v the meter ratio is 5/5A.