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A pseudo-op is an assembly language instruction that specifies an operation of the assembler i.e
about the base register & its contents e.g. USING instruction. On the other hand, a machine-op instruction. That
represents a machine instruction to the assembler e.g. BR instruction is a machine-op instruction
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How do you say the french alphebet?
The letters are the same, but here is the pronunciation.A-ahB-bayC-sayd-daye-uhf-efg-jayh-ashi-ej-geek-kahl- lm- mn- no - op- payq- cuer- rs-st- tayu- oov- vayw- double vayx- ixy- eegleckz- zed
Sample problems and solutions in finding the distance between a point and the line?
The distance between a point and a line is the length of the perpendicular line drawn from the point to the line.The easiest way is with vectors. Call P1 and P2 two points on the line, and P3 the third point.Call the intersection of the line and the perpendicular from the point to the line P.Now if the dot product of two vectors is zero, they are perpendicular. Sowe look at the dot product of (P2-P1)dot(P3-P)=0We can solve for P and find the intersection. Then find the length of that segment. Here is an example using the line 2x+3y=7 and the point (9,5) First, lets find a vector representation of the line. If x=0, y=7/3 and if y=0, x=7/2. So the vector (7/2,-7/3)t represents the line. Now we want a line through the point (9,5) perpendicular to the line 2x+3y=7 So let's call the point of intersection (x,y). Then the vector (9-x,5-x)t must be perpendicular to the first vector. We use the dot product. (9-x,5-y) dot (7/2,-7/3)=0 so evaluate the dot product and we have 7/3y-7/2x+119/6=0 Now solve the system of equations 7/3y-7/2x+119/6=0 2x+3y=7 the solution is (5,-1) To finish the problem, find the distance between (5,-1) and (9,5) using the distance formula. This distance is 2(square root 13)If you would rather not use vectors, that's fine too.Let the original line be y=mx+b and the point you want to find the distance to (x1,y1)You can use the formula that this distance is(y1-mx1-b)/square root of (m^2+1). You really need the absolute value of the expression in the numerator. The advantage of the first method is it can be used in any dimension. So it can find the distance from a point to a plane in 3d or even higher dimension. Here is a worked example. Y You can model other problems and do them the same way.What is the distance from the point (9,5) to the line 2x+3y=7Let A be the point (9,5) and P be the point in which the normal meets the given line.So AP is normal to 2x+3y=7 andwe write AP as AP=(2k,3k) for some scalar k.Now OP=OA+AP where O is the origin.The coordinate of of P are (9+2k,5+3k) and sine P lies on the line we have2(9+2k)+3(5+3k)=7. Now solve for k and you find k=-2So AP =(-4,-6) and the length of AP using the distance formula is square root of (16+36)=2Square root of 13. Since OP=OA+Ap we find P is the point (5,-1)Solution 2The point C(0,7/3) lies on the line AC=(-9,-8/3) Let theta be the angle between AC and the normal vector N=(2,3)AP=|ACx Cos theta)=AC|AC dot N/ACx|N|=18+8/Square root of 13=2square root of 13.Solution 3: Here is one last approach that I would say is geared toward Alg1 or Alg 2 students. It does not use vectors or formulas, just some basic Algebra concept. the line is 2x+3y=7, we know that a perpendicular line must have a slope that is the negative reciprocal of the slope of the line2x+3y=7, So let's write that line in slope intercept form. 3y=-2x+7 and y=-2/3x+7/3 So the slope of the perpendicular line is 3/2. Now we have a point and a slope so we have a line using point slope form. The slope is 3/2 and the point is (9,5) (y-5)=3/2(x-9) which we can write as y=5+3/2x-27/2 or y=3/2x-17/2 Now we find the point where this line intersects the original line. We do this because then we need only find the distance between two points which we can do with the distance formula. y=3/2x-17/2y=-2/3x+7/3 So solve them easily I will rewrite them both 2y=3x-34/23y=-2x+7 Solve these two simultaneous equations, find the point then just find the distance from that point to the original one. When we solve them, we find the intersection, which is the point we are looking for is (5,-1). The distance from that point to (9,5) is the square root of [(9-5)2 +(5+1)2 ]=2square root(13) as above.
Difference between decca and coop high school courses?
what is different between school and co-op
Why must the operand field of the EQU pseudo-op be evaluated in pass 1?
We need to find the S.T so we need to find the values of the Symbols!!! The format of the EQU pseudo-op is : Lable EQU operand, so we need to find the value of the label in order to find the S.T
What is the difference between a post op transsexual and a pre op transsexual?
Post-op is after the reassignment surgery (they now have the parts of the sex opposite to what they were declared at birth). A pre-op transsexual person is someone who hasn't undergone sexual reassignment surgery. They still have the genitals they were wrongly born with.
What is the difference between operand and opcode?
op code is used as the value of instruction . And operand is address location where the instruction can meet.
What is the difference between an co-op and a condo?
In a condominium, you hold title to your unit and own real estate in common with all other owners. In a co-op, you own shares in a corporation and are assigned a unit to which you do not hold clear title.
What is the important machine on the club penguin field op which ends tomorrow?
seaside projects
What is the difference between cooperation and peer review?
cooperation involves co-op, 2 random pupils peer review, "peer" requires you to have friends its easy
Why must symbols appearing in length and repetition factors of the DC pseudo-op be self defining or previously defined symbols?
they are used to reserve bytes at the time the code is assembled.
Difference between instrumentation and operational amplifiers?
An instrumentation amplifier is made out of 2 or 3 operational amplifiers.
Does op-amps use internal capacitive coupling between stages?
No. An op-amp is a DC coupled device.
What is different in oc 20mg and op 20mg?
The difference between the two is they will no longer be making oc 20's or any oc's for the matter. the op 20 is the same opiate, just gel form, so they can be less likely to abuse, such as snorting or shooting. So to answer your question, the op 20 is the same drug as oc 20, just a gel not a powder.
What is the difference between open loop and closed loop gains of an op amp?
A: Usually by looking at the specification for that op-amp and there will be accuracy deviation from device to device. To use it open loop is practically impossible all it tells from specification that there will be enough gain when the loop is closed and the max frequency available
