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The KB value is listed below:

pKa + pKb - 14

pKa = -log10 (Ka), Ka of acetic acid = 1.8*10^-5

pKa = 4.74, pkb = 9.255

9.255 = -log10(Kb), Kb = 5.56*10^-10

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9y ago
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12y ago

Ka (CH3COOH)= 6,5 *10-5

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Q: What is the Ka for acetic acid CH3COOH?
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