No. CH3COOH is a weak acid known as acetic acid or ethanoic acid.
It is a so called Amfolyt. Both acid and base.
The compound is ethanoic acid, and it is not a base.
CH3COOH is a monobasic acid because it is completely neutralised by one mole of a base. E.g CH3COOH + H20 -> CH3COO- + H30+
.Vinegar is made up of Acetic Acid(CH3COOH) which is a weak acid. On the other hand, sodium Hydroxide is a strong base.
Caustic soda is sodium hydroxide (NaOH), which is a strong base. Vinegar, a weak acid, is dilute acetic acid (CH3COOH). When combined, they undergo a neutralization reaction producing water and the salt sodium acetate (NaCH3COO). The balanced chemical equation is written below.NaOH(aq) + CH3COOH(aq) --> H2O(l) + NaCH3COO(aq)
CH3COOH is a acid. It is a weak acid.
It is a so called Amfolyt. Both acid and base.
The compound is ethanoic acid, and it is not a base.
CH3COOH is a monobasic acid because it is completely neutralised by one mole of a base. E.g CH3COOH + H20 -> CH3COO- + H30+
.Vinegar is made up of Acetic Acid(CH3COOH) which is a weak acid. On the other hand, sodium Hydroxide is a strong base.
Ch3cooh
Caustic soda is sodium hydroxide (NaOH), which is a strong base. Vinegar, a weak acid, is dilute acetic acid (CH3COOH). When combined, they undergo a neutralization reaction producing water and the salt sodium acetate (NaCH3COO). The balanced chemical equation is written below.NaOH(aq) + CH3COOH(aq) --> H2O(l) + NaCH3COO(aq)
HCL is completely (or nearly 100%) ionized because it is a strong acid whereas the CH3COOH is partially ionized as it is a weak acid.
Acetic Acid or ethanoic acid {CH3COOH}.BEING ACID,IT TURNS BLUE LITMUS RED.IT IS SOUR.
It is a strong base.
Because hydroxide (OH-) is a strong base reacting completely with undissociated acetic acod (CH3COOH) to leave only acetate ions (CH3COO-) and water when completed.
'HC2H3O2' is a rather poor way of writing the formula for ethanoic(acetic) acid. It is usually written as 'CH3COOH'.