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Q: What is the Keq expression for this equilibrium?
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What is the expression that represents the equilibrium constant expression for H2SO3?

H2SO3 will ionize to H+ + HSO3-. The Keq = [H+][HSO3-]/[H2SO3]HSO3- will ionize to H+ + SO3^2-. The Keq = [H+][SO^2-]/[HSO3-] ... very small value


What is the symbol for the equilibrium constant?

Keq= ([A]a[B]b/[C]c[D]d)


What is keq for the reaction n2 3h2 2nh3 if the equilibrium concentrations are nh3 2 m n2 3 m and h2 1 m?

K(eq)= 1.33


How does reaction quotient predicts the direction of a reaction?

The reaction quotient is the ratio of products to reactants not at equilibrium. If the system is at equilibrium then Q becomes Keq the equilibrium constant. Q = products/reactants If Q < Keq then there are more reactants then products so the system must shift toward the products to achieve equilibrium. If Q > Keq then there are more products than reactants and the system must shift toward the reactants to reach equilibrium.


Which species are left out from the Keq expression?

Solids and liquids


How is the equilibrium of a reaction determined?

Molarity of products divided by reactants Keq=(products)/(reactants)


What is the Keq for the reaction N2 plus 3H2 2NH3 if the equilibrium concentrations are (NH3)3 M (N2) 2 M and (H2) 1 M?

keq = 1.125


What is Keq for the reaction N2 plus 3H2 2NH3 if the equilibrium concentrations are NH3 3 M N2 2 M and H2 1 M?

keq = 1.125


Why does a numerically large Keq mean that the products are favored in an equilibrium system?

Because it means that the equilibrium mixture contains more product than reactants.


What does it mean if Keq equals 1?

Products and reactions are equally favored in the reactions


How is the equilibrium constant of a reaction determined?

Molarity of products divided by reactants Keq=(products)/(reactants)


What does it mean when a reaction has a large value of KMeq?

If a reaction creates far more products than reactants, the numerator is large and the denominator is small. That means Keq will be large. So when Keq is large, equilibrium is to the far right of the reaction. A reaction that goes to completion would have an infinite Keq, since the concentration of reactants goes all the way to zero.If few products form, and many reactants remain, the numerator is small and the denominator is large. So a small Keq means that equilibrium is far to the left.you're welcome.